Which of the following occurs during the evolution of a star?

The speed v of a sound wave traveling in a medium that has bulk modulus b and mass density ρ (mass divided by the volume) is v=b

PilotLPTM [1.2K]

As it is given that Bulk modulus and density related to velocity of sound

$v = \sqrt{\frac{B}{\rho}}$

by rearranging the equation we can say

$B = \rho * v^2$

now we need to find the SI unit of Bulk modulus here

we can find it by plug in the units of density and speed here

$B = \frac{kg}{m^3} * (\frac{m}{s})^2$

so SI unit will be

$B = \frac{kg}{m* s^2}$

SO above is the SI unit of bulk Modulus

3 0

3 years ago

How many volts would it take to push 1 amp through a resistance of 1 ohm?

ELEN [110]

V=I x R so V= 1 x 1 =1V

5 0

2 years ago

Read 2 more answers

Eric drops a 2.20 kg water balloon that falls a distance of 45.08 m off the top of a

Marianna [84]

Answer:

972 J

Explanation:

At the bottom, all the gravitational potential energy was converted into kinetic energy. If you calculate the GPE, its value will be the same that the KE at the bottom. The GPE can be calculated this way:

GPE = mass×gravity×heigth

GPE = 2.2×9.8×45.08 ≈ 972

4 0

2 years ago

Welcome to this IE. You may navigate to any page you've seen already using the IE Outline tab on the right. A particle beam is m

Genrish500 [490]

Answer:

the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

Explanation:

Given the data in the question;

Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J

Mass of proton = 1.673 × 10⁻²⁷ kg

Charge of proton = 1.602 × 10⁻¹⁹ C

distance d = 2 m

we know that

Kinetic Energy = Charge of proton × Potential difference ΔV

so

Potential difference ΔV = Kinetic Energy / Charge of proton

we substitute

Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )

Potential difference ΔV = 20287.14 V

Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;

E = Potential difference ΔV / distance d

we substitute

E = 20287.14 V / 2 m

E = 10143.57 V/m or 1.01 × 10⁴ V/m

Therefore, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

3 0

2 years ago

g Where is the dielectric constant and A is the area of the capacitor plates. The charge q and voltage Vc across the capacitor p

aev [14]

Answer:

Capacitor and the dielectrics:

"The capacitor is a charge,q storing device as it is subjected to the potential difference between the different plates and thus results in the difference of charge decomposition between the two plates."

Formula:C= ∈°(A/d),

Unit: Farad,F.

Purpose of the Dielectrics:

In order to store or hold the optimum number of charge particles,q between the plates we have a number of insulators which are used as the medium between the two plates.While, it separates both the plates from one another.

Explanation:

Dielectric Constants in the capacitors:

In order to hold the number of charges in between the plates of the capacitor a specific medium or substrate is placed(mostly the insulators). As it covers the area between the two capacitors, while it can decrease and increase by the action of the movable plate of the capacitor.

Now, it increase the capcitative power of the capacitor by decreasing the potential difference between the two plates, along with which the electromagnetic field is also greatly reduced.As the interaction between the two plates is greatly reduced, as they are covered and well protected by the sheet or membrane of insulting medium around them.

6 0

3 years ago