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soldier1979 [14.2K]
3 years ago
8

Stacy reads that a 50:50 mixture of methanol and water is best for keeping a car’s radiator from freezing when the temperature g

oes down to –40°C. Design an experiment to test this finding. You have a –40°C freezer, water, methanol, graduated cylinders to measure volume, several plastic beakers, and a watch at your disposal. Be sure to state your hypothesis, procedure, and any controls in your experiment. What are the dependent and independent variables? Explain the possible results if your hypothesis is true.
Chemistry
2 answers:
salantis [7]3 years ago
5 0
1. The hypothesis for this is experiment is that the 50:50 of methanol-water mixture will not turn to solid when the temperature reaches to -40°C.

2. The procedure for this is measuring equal volumes of water and methanol using the graduated cylinder. You can measure 100 mL of water and 100 mL of methanol using the graduated cylinder. Then, mix them in the beaker. Next, measure 200 mL of water, and another 200 mL of methanol. Don't mix them. Also, make a 60:40 mixture by measuring 120 mL of water and 80 mL of methanol, then mix them together. Place them all in the refrigerator at the same time. Record the time when they would freeze to solid.

3. The controls for this experiment are the 200 mL water alone, and the 200 mL methanol alone.

4. The independent variable in here is the time, while the dependent variable is the temperature of the mixtures.

5. If the hypothesis turns out to be true, then all the mixtures prepared should freeze and become solid after a certain period of time, with the exception of the 50:50 mixture. The 50:50 mixture should still remain as a liquid even when left overnight.
Inessa05 [86]3 years ago
3 0

<span>Hypothesis: If a mixture of methanol and water is made with an equal amount of water and methanol, more water than methanol, and less water than methanol, then the mixture with less water than methanol will be the best at resisting freezing when in temperatures of -40 degrees Celsius.</span><span> <span>You have to first measure equal amounts of methanol and water in graduated cylinders then pour into plastic beaker. For a second trial measure two parts water and one part methanol then pour them in separate beaker.  </span></span>

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It requires 334 kJ of heat to melt 1 kg of ice. The largest known iceberg had a volume of about 3.1 x 1013 m³. How much heat was
umka21 [38]

The  amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.

<h3>What is the amount of heat required to melt an iceberg that has a volume of about 3.1 x 1013 m³?</h3>

The heat required to melt a unit mass of ice is known as the latent heat of fusion.

The latent heat of fusion of ice of 1 kg= 334 kJ of heat

Mass of iceberg = 3.1 x 10¹³ m³ * 917 kg = 2.8427 * 10¹⁶ kg

Amount of heat required = 2.8427 * 10¹⁶ * 334 = 9.58 * 10¹⁸ kJ.

Therefore, the amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.

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8 0
2 years ago
use dimensional analysis to determine how many atoms of o2 produced in a reaction that yields 2 mol of o2
Alex73 [517]

The number of atoms of oxygen is 2.4 * 10^24.

<h3>How many atoms are produced?</h3>

We know that mole of a substance contains the Avogadro's number of atoms. The Avogadro's number gives the number of atoms, molecules, ions and atoms that could be found in one mole of a substance.

Now;

Given that ;

1 mole of oxygen contains two atoms of oxygen, the number of atoms that are contained in 2 moles of the oxygen molecule is;

2 * 2 * 6.023 * 10^23

= 2.4 * 10^24

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2 years ago
If a gas is 16 times as heavy as hydrogen which will diffuse faster and by what ratio​
vodka [1.7K]

Answer:

1. Hydrogen will diffuse faster.

2. The ratio of diffusion of hydrogen gas to that of the unknown gas is 4 : 1

Explanation:

Let the rate of diffusion of hydrogen gas, H2 be R1

Let the molar mass of H2 be M1

Let the rate of diffusion of the unknown gas be R2.

Let the molar mass of the unknown gas be M2.

Molar mass of H2 (M1) = 2x1 =2g/mol

Molar mass of unknown gas (M2) = 16 times that of H2

= 16 x 2 = 32g/mol

1. Determination of the gas that will diffuse faster. This is illustrated below:

R1/R2 = √(M2/M1)

R1/R2 = √(32/2)

R1/R2 = √16

R1/R2 = 4

Cross multiply

R1 = 4R2

From the above calculations, we can see that the rate of diffusion H2 (R1) is four times the rate of diffusion of the unknown gas (R2).

Therefore, hydrogen will diffuse faster.

2. Again, from the calculations made above, the ratio of diffusion of hydrogen (R1) to that of the unknown gas (R2) is given by;

R1/R2 = 4

Therefore, the ratio of diffusion of hydrogen (R1) to that of the unknown gas (R2) is:

4 : 1

7 0
3 years ago
2. How many moles of Na2CO3 are available?
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<em>malai</em><em> </em><em>aaudaina</em><em> </em><em>aati</em><em> </em><em>jabo</em><em> </em><em>tapai</em><em> </em>

<em>lai</em><em> </em><em>aaudaina</em><em> </em>

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The answer is 2300 mg which is equal to one teaspoon of salt
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3 years ago
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