Answer:
Mass of iodine = 1954.26 g
Explanation:
Given data:
Mass of chlorine react = 546 g
Mass of iodine produced = ?
Solution:
Chemical equation:
2NaI + Cl₂ → 2NaCl + I₂
Number of moles of chlorine:
Number of moles = mass/molar mass
Number of moles = 546 g/71 g/mol
Number of moles = 7.7 mol
Now we will compare the moles of chlorine with iodine.
Cl₂ : I₂
1 : 1
7.7 : 7.7
Mass of iodine:
Mass = number of moles × molar mass
Mass = 7.7 mol × 253.8 g/mol
Mass = 1954.26 g
Since we assume both reactants have 1 equivalent of H+ and OH- ions, we can balance the moles out. The acid of concentration x will have (x M)(0.035 L) = 0.035x moles of acid. Meanwhile, for the base: (0.432 M)(0.0246 L) = 0.0106 moles of base. Since these must be equivalent:
0.035x = 0.0106x = 0.304 M
This has only only three sig figs because it is 546.000 the zeros are just place holders so thus meaning they are not significant. It is just another way to write 546 because in that number there is also 3 sig figs. They are just trying to throw you off. Just watch out because if the example is 540 then it is just two significant digits, and it were to be 540. then it be three cause that "." makes the zero significant. <span />
Ca3N2 is your answer<span> </span>
Answer:
Following are the responses to the given question:
Explanation:
calculating the HOI:
So, in the above compund there are three bounds or we can say that one is double and two bound is single.
Please find the attachment file of the Function group:
In the above given conditon compound doesn't include the alkene functional group that is absense of
, and compound include 
So, please find the attached file of the structure of the compound:
