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Elis [28]
3 years ago
10

A strip of copper metal is placed in an aqueous sodium chloride solution. According to the standard reduction potential below, w

hich of the following would be observed A. No reaction occurs B. Bubbles of gas would be observed C. A blue color would form in the solution D. Crystals of copper (II) chloride would form on the strip of copper
Physics
1 answer:
oee [108]3 years ago
3 0

Answer:

The answer to A strip of copper metal is placed in an aqueous sodium chloride solution. According to the standard reduction potential below, is Option A) No reaction occurs

Explanation:

Aqueous sodium chloride solution is similar to salt and water mixed together.

Copper doesn’t dissolve in salty water. However, exposure of the metal to air and then to water results in an oxide layer on the surface of copper which is referred: the dull reddish brown copper(I) oxide and this exists in an equilibrium with the outer oxide layer of black copper(II) oxide.

If you put a strip of copper metal is placed in an aqueous sodium chloride solution, you will not observe any reaction because the oxide layer on the surface of copper is too thin for to be noticed other than by a dulling or darkening of the surface, not thick enough to be obvious.

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You are getting bored as you are stuck at home, and want to find out the effective 'spring constant' of random objects. You find
Luda [366]

Given Information:  

Mass of sock = 0.23 kg

Stretched length of sock = x = 2.54 cm = 0.0254 m

Required Information:  

Spring constant = k = ?

Answer:  

Spring constant = k = 88.82 N/m

Explanation:  

We know from the Hook's law that

F = kx

Where k is spring constant, F is the applied force and x is length of sock being stretched.

k = F/x

Where F is given by

F = mg

F = 0.23*9.81

F = 2.256 N

So the spring constant is

k = 2.256/0.0254

k = 88.82 N/m

Therefore, the spring constant of the sock is 88.82 N/m

4 0
3 years ago
Read 2 more answers
Matter can undergo chemical reactions and nuclear reactions. Which
NeX [460]

Answer:

<em>D.) state of matter</em>

Explanation:

it can undergo chemical but not nuclear.

6 0
2 years ago
An archer draws her bow and stores 34.8 J of elastic potential energy in the bow. She releases the 63 g arrow, giving it an init
elena-14-01-66 [18.8K]

Answer:

Approximately 71\%.

Explanation:

The formula for the kinetic energy \rm KE of an object is:

\displaystyle \mathrm{KE} = \frac{1}{2}\, m \cdot v^2,

where

  • m is the mass of that object, and
  • v is the speed of that object.

Important: Joule (\rm J) is the standard unit for energy. The formula for \rm KE requires two inputs: mass and speed. The standard unit of mass is \rm kg while the standard unit for speed is \rm m \cdot s^{-1}. If both inputs are in standard units, then the output (kinetic energy) will also be in the standard unit (that is: joules,

Convert the unit of the arrow's mass to standard unit:

m = 63\; \rm g = 0.063\; \rm kg.

Initial \rm KE of this arrow:

\begin{aligned}\mathrm{KE} &= \frac{1}{2} \, m \cdot v^2 \\ &= \frac{1}{2}\times 0.063\; \rm kg \times \left(\rm 28 \; m \cdot s^{-1}\right)^2 \\ &\approx 24.696\; \rm J\end{aligned}.

That's the same as the energy output of this bow. Hence, the efficiency of energy transfer will be:

\displaystyle \frac{24.696\; \rm J}{34.8\; \rm J} \times 100\% \approx 71\%.

8 0
3 years ago
Which sequence does<br> the energy transformation in an automobile engine.
Vera_Pavlovna [14]

Answer:

Mechanical

Explanation:

7 0
3 years ago
Suppose a pendulum bob is swinging back and forth. If the highest point is 12.5 cm above the lowest point, what would be speed o
Colt1911 [192]

Answer:

The speed of the bob  when it passes the lowest point  V = 1.57 \frac{m}{s}

Explanation:

Given data

H = 12.5 \ cm = 0.125 \ m\\

When a pendulum swinging back & forth then at highest point the velocity is zero and lowest point velocity is maximum.

Velocity at lowest point is given by  

V = \sqrt{2 g H}

V = \sqrt{2 (9.81)(0.125)}

V = 1.57 \frac{m}{s}

Therefore the speed of the bob  when it passes the lowest point V = 1.57 \frac{m}{s}

7 0
3 years ago
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