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Elis [28]
3 years ago
10

A strip of copper metal is placed in an aqueous sodium chloride solution. According to the standard reduction potential below, w

hich of the following would be observed A. No reaction occurs B. Bubbles of gas would be observed C. A blue color would form in the solution D. Crystals of copper (II) chloride would form on the strip of copper
Physics
1 answer:
oee [108]3 years ago
3 0

Answer:

The answer to A strip of copper metal is placed in an aqueous sodium chloride solution. According to the standard reduction potential below, is Option A) No reaction occurs

Explanation:

Aqueous sodium chloride solution is similar to salt and water mixed together.

Copper doesn’t dissolve in salty water. However, exposure of the metal to air and then to water results in an oxide layer on the surface of copper which is referred: the dull reddish brown copper(I) oxide and this exists in an equilibrium with the outer oxide layer of black copper(II) oxide.

If you put a strip of copper metal is placed in an aqueous sodium chloride solution, you will not observe any reaction because the oxide layer on the surface of copper is too thin for to be noticed other than by a dulling or darkening of the surface, not thick enough to be obvious.

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3 years ago
What is force <br>what is the importance of force​
frutty [35]

Force is the ability to cause masses to accelerate.

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2 years ago
A ball with a mass of 275 g is dropped from rest, hits the floor and rebounds upward. If the ball hits the floor with a speed of
Alla [95]

Answer:

Change in momentum is 1.1275 kg-m/s

Explanation:

It is given that,

Mass of the ball, m = 274 g = 0.274 kg

It hits the floor and rebounds upwards.

The ball hits the floor with a speed of 2.40 m/s i.e. u = -2.40 m/s  (-ve because the ball hits the ground)

It rebounds with a speed of 1.7 m/s i.e. v = 1.7 m/s (+ve because the ball rebounds in upward direction)

We have to find the change in the ball's momentum. It is given by :

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\Delta p=0.275\ kg(1.7\ m/s-(-2.4\ m/s))

\Delta p=1.1275\ kg-m/s

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3 0
3 years ago
A conducting loop in the form of a circle is placed perpendicular to a magnetic field of 0. 50 t. If the area of the loop decrea
Kisachek [45]

The induced emf in the loop is  -1500 μ V or  - 0.0015 V  .

According to the question

A conducting loop in the form of a circle is placed perpendicular to a magnetic field of 0. 50 t.  

i.e

Magnetic field (B) = 0. 50 T

Area of circle or loop = \pi r^{2}  

Now,

The area of the loop decreases at a rate of 3. 0 × 10⁻³ m/s

i.e

dA = 3. 0 × 10⁻³ meter²

dt = 1 sec  

As per the formula of Induced e.m.f in the loop

emf is dependent on number of turns of coil, shape of the coil, strength of magnet and speed with which magnet is moved. Emf is independent of resistivity of wire of the coil.

e=-B*\frac{dA}{dt}

where A is the area of the loop.

Now ,

Substituting the values in the formula

e=-B*\frac{dA}{dt}

e= - 0.50 *\frac{ 3 * 10^{-3}}{1}    

e = - 0.0015 V

OR

e = -1500 * 10⁻⁶ V

e =  -1500 μ V

Negative just signifies emf will such be induced that current induced will oppose change in magnetic field though it

To know more about induced emf here:

brainly.com/question/16764848

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5 0
2 years ago
The manufacturer of a 9V dry-cell flashlight battery says that the battery will deliver 20 mA for 80 continuous hours. During th
Maksim231197 [3]

Answer:

17280 J or 17.28 kJ

Explanation:

Given that the voltage drop,

U = U2 - U1

U = 9 - 6

U = 3V

Also, we're told that the current, I is equal to 20 mA with the discharge time, t being 80 hrs.

Converting the time from h oi urs to seconds, we have

t = 80 * 3600

t = 288000

Now, to find the energy needed, we're going to use the formula

w = pt, where p = U * I

p = 3 * 20*10^-3

p = 60*10^-3

w = 60*10^-3 * 288000

w = 17280 J or 17.28 kJ

Therefore, the total energy the battery delivers in the 80 hrs is 17.28 kJ

5 0
2 years ago
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