What is transferred through sound waves?
1 answer:
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Answer:
Position = behind the mirror
Nature = Virtual and Erect
Size = : Diminished
Explanation:
Sign convention-Distance measured to the left of pole is negative and to the right of pole is positive.
Object distance = u = -20 cm
Focal length = f = Radius of curvature/2 = 30/2 = 15 cm
We have to use mirror formula to find image distance.
Since the image distance is positive, it is formed behind the mirror or a virtual image is formed.
Magnification =
Height of the object = 5 cm
Height of the image =
Since the height of the image is positive and less than the size of object,it is erect and diminished.
Here,
m=80 kg
R= 6.4*10^6 m
and t=24*3600=86400 s
Centripetal acceleration:
a=ω²r
=(2
/86400)^2 * 6.4*10^6
=0.034 m/s²
m=80 kg
R= 6.4*10^6 m
and t=24*3600=86400 s
Centripetal acceleration:
a=ω²r
=(2
=0.034 m/s²