3 years ago

Explain, in terms of electrons, why the compound containing calcium and chlorine is classified as an ionic compound.

Chemistry

1 answer:

Pavel [41]3 years ago

4 0

Because the reaction occurs between a metal and non metal
CL=2,8,7
C

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I THINK it's gained a proton

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Which is an example of a pure substance? A. coffee B. helium C. vinegar D. trail mix

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B. Helium

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Mercury has an atomic number of 80 and a mass number of 200.

denis23 [38]

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At a certain temperature the value of the equilibrium constant, Kc, is 1.27 for the reaction. 2As (s) + 3H2 (g) ⇌ 2AsH3 (g) What

Bess [88]

Answer:

$0.887$

Explanation:

Hello,

In this case, the law of mass action for the first reaction turns out:

$Kc=\frac{[AsH_3]^2}{[As]^2[H_2] ^3}=1.27$

Now, for the second reaction is:

$Kc=\frac{[As][H_2] ^{3/2}}{[AsH_3]}$

Therefore, by applying square root for the first reaction, one obtains:

$\sqrt{Kc} =\sqrt{\frac{[AsH_3]^2}{[As]^2[H_2] ^3}} =\sqrt{1.27}$

$\frac{\sqrt{[AsH_3]^2} }{\sqrt{[As]^2} \sqrt{[H_2] ^3} } =\sqrt{1.27}$

$\sqrt{1.27}=\frac{[AsH_3]}{[As][H_2] ^{3/2}}$

Finally, since Kc is asked for the inverse reaction, one modifies the previous equation as:

$Kc'=\frac{1}{\sqrt{1.27} }=\frac{[As][H_2] ^{3/2}}{[AsH_3]}=0.887$

Best regards.

8 0

3 years ago

What is the standard emf of a galvanic cell made of a cd electrode in a 1.0 m cd(no3)2 solution and a cr electrode in a 1.0 m cr

Natali5045456 [20]

Standard reduction potential of Cd2+ = -0.403 v
Standard reduction potential of Cr3+ = -0.74 v

Here, reduction potential of Cd2+ is higher as compared to Cr3+. Hence, it will preferentially undergo reduction.

The electrochemical cell is represented as
Cr/Cr3+// Cd2+/Cd

Now, standard EMF of cell = E = ECd2+/Cd - ECr3+/Cr
= - 0.403. - (-0.74)
= 0.337 v

8 0

3 years ago