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3 years ago

What two things increase the gravitational pull between two objects?

2 answers:

8 0

Two things that increase the gravitational pull between two objects are decreasing the distance between the objects and increasing the mass of the objects. the force due to gravity is F = GMm/(r^2) where G is the gravitational constant, M and m are the masses of the two objects, and r is the distance between them.

stiv31 [10]3 years ago

5 0

In order to increase the gravitational forces between two objects,
you have exactly two choices:

-- Increase the product of the two masses.

-- Decrease the distance between their centers of mass.

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Which characteristics describe a point charge?

wolverine [178]

Answer:

Explanation:

becauase i just tooke the test

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3 years ago

Which of the following is the best definition of vaporization

Vinvika [58]

Change of a liquid to a gas

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3 years ago

A 7.5 cm object is 14 cm from a concave lens, which has a focal length of –7 cm. Its image is 5 cm in front of the lens. What is

Rama09 [41]

Given conditions:
height of object = 7.5cmdistance of object from mirror = 14 cmfocus length = -7 cmimage distance = ?
Using mirror formula:
1/(focus length) = 1/(object distance) + 1/(image distance)
or, -1/7 = 1/14 + 1/(image distance)
or, image distance = -4.66cm (the image formed is a virtual image)

Also, magnification of image is:
image height /height of object = - image distance /object distance
or, image height = - image distance / object distance * height of object
or, image height = -(-4.66) / 14 * 7.5 = 2.49 = 3(nearest whole number)

3 0

3 years ago

Read 2 more answers

Two charged spheres are 20 cm apart and exert an attractive force of 8 x 10-9 n on each other. What will the force of attraction

Pavel [41]

Answer:

$3.2\cdot 10^{-8} N$

Explanation:

The inital electrostatic force between the two spheres is given by:

$F=k\frac{q_1 q_2}{r^2}$

where

$F=8\cdot 10^{-9} N$ is the initial force

k is the Coulomb's constant

q1 and q2 are the charges on the two spheres

r is the distance between the two spheres

The problem tells us that the two spheres are moved from a distance of r=20 cm to a distance of r'=10 cm. So we have

$r'=\frac{r}{2}$

Therefore, the new electrostatic force will be

$F'=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(r/2)^2}=4k\frac{q_1 q_2}{r^2}=4F$

So the force has increased by a factor 4. By using $F=8\cdot 10^{-9} N$ , we find

$F'=4(8\cdot 10^{-9} N)=3.2\cdot 10^{-8} N$

6 0

3 years ago

Lonnie pitches a baseball of mass 0.500 kg. The ball arrives at home plate with a speed of 35.0 m/s and is batted straight back

Andreyy89

Answer:

Explanation:

The impulse equation is

Δp = FΔt, where Δp = final momentum - initial momentum, F is the Force exerted on an object, and Δt is the change in time. In this equation,the entire right side defines the impulse. In other words, FΔt is the impulse; thus the change in momentum an object experiences is due to its change in impulse and is directly proportional to it.

Therefore, once we find the change in momentum, that is the impulse the object experiences. Δp = final momentum - initial momentum, where

p = mv and p is momentum.

$p_f=(.500)(50.0)$ so

$p_f=25.0$ and

$p_i=(.500)(35.0)$ so

$p_i=17.5$ ; therefore,

Δp = 25.0 - 17.5 = 7.5 $\frac{kg*m}{s}$ which is the unit for momentum

7 0

3 years ago