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MArishka [77]
3 years ago
5

What two things increase the gravitational pull between two objects?

Physics
2 answers:
Artyom0805 [142]3 years ago
8 0
Two things that increase the gravitational pull between two objects are decreasing the distance between the objects and increasing the mass of the objects. the force due to gravity is F = GMm/(r^2) where G is the gravitational constant, M and m are the masses of the two objects, and r is the distance between them.
stiv31 [10]3 years ago
5 0

In order to increase the gravitational forces between two objects,
you have exactly two choices:

-- Increase the product of the two masses.

-- Decrease the distance between their centers of mass.


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Answer:

No

Explanation:

Your answer will be no because Mars has less gravity then Earth does but you would still have the same amount of mass therefor If someone goes to Mars and goes back to Earth they would not weigh the same as they did on earth.Hope it helps you!

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When energy changes form, energy is...<br><br>A) lost.<br>B) created.<br>C) not lost or created.
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A motorcycle that is slowing down uniformly. The motorcycle covers 1 ????m=1000 m in 80 sec⁡. The motorcycle then covers the nex
Lynna [10]

Answer:

Part a)

acceleration = -0.042 m/s/s

Part b)

initial speed = 14.17 m/s

final speed = 5.77 m/s

Explanation:

Part a)

Let the initial velocity of the motorcycle is

v_i = v_o

now at the end of 80 s let the speed is

v_f = v_1

after another 120 s let the speed will be

v_f' = v_2

now we know that

d = \frac{v_i + v_f}{2} (t)

d = \frac{v_o + v_1}{2}(80)

1000 = 40(v_o + v_1)

also we know that

v_1 - v_o = a(80)

also we have

1000 = \frac{v_1 + v_2}{2}(120)

1000 = 60(v_1 + v_2)

now we can say

(v_2 + v_1) - (v_o + v_1) = \frac{50}{3} - \frac{50}{2}

also we know

v_2 - v_o = a(120 + 80)

-8.33 = 200 a

a = -0.042 m/s^2

Part b)

now we have

v_1 + v_o = 25

v_1 - v_o = (-0.042)(80)

v_1 = 10.83 m/s

so the starting velocity of the trip is

v_o = 25 - 10.83 = 14.17 m/s

now speed after t = 200 s is given as

v_2 = v_o + at

v_2 = 14.17 - (0.042)(200)

v_2 = 5.77 m/s

5 0
3 years ago
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