A hockey player makes a slap shot exerting a constant force of 40.0 newtons on the puck for .2 seconds. What is the magnitude of
1 answer:
Answer:
Magnitude of impulsive force is <u>8 N.s</u>.
Explanation:
Given:
Force acting on the puck is,
Time interval for which the force acts is,
We are asked to find the impulsive force.
Impulsive force acting on a body is the sudden change in the momentum of the body due to the application of a large constant force for a very small interval of time.
Here, the hockey player applies a large force of 40 N for a very short interval of time. So, the impact on the puck is measured as Impulse and is represented by 'J'.
Impulse in terms of applied force and time interval is given as:
Plug in the given values and solve for 'J'. This gives,
Therefore, the magnitude of impulsive force is 8 N.s.
You might be interested in
The mechanical energy for the first and the second ball is
Mass of the first ball = 20 kg
The initial speed at which a cannonball is fired from a cannon =1000 m/s
The angle made by the cannonball while being fired from the cannon = 37°
The maximum height reached by the first ball is,
The maximum height of the first cannonball is 17478.69 m.
The initial speed at which a cannonball is fired from a cannon =1000 m/s
The angle made by the cannonball while being fired from the cannon = 90 °
For the first ball, total mechanical energy= Potential energy at maximum height + kinetic energy at the maximum height
So, the total mechanical energy is,
= mgh \: + \frac{1}{2}mv {}^{2} _{x}[/tex]
Therefore, the total mechanical energy for the first and the
To know about energy, refer to the below link:
#SPJ4