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Gwar [14]
3 years ago
10

A hockey player makes a slap shot exerting a constant force of 40.0 newtons on the puck for .2 seconds. What is the magnitude of

the impulse given to the puck?
Physics
1 answer:
Taya2010 [7]3 years ago
6 0

Answer:

Magnitude of impulsive force is <u>8 N.s</u>.

Explanation:

Given:

Force acting on the puck is, F=40.0\ N

Time interval for which the force acts is, \Delta t=0.2\ s

We are asked to find the impulsive force.

Impulsive force acting on a body is the sudden change in the momentum of the body due to the application of a large constant force for a very small interval of time.

Here, the hockey player applies a large force of 40 N for a very short interval of time. So, the impact on the puck is measured as Impulse and is represented by 'J'.

Impulse in terms of applied force and time interval is given as:

J=F\Delta t

Plug in the given values and solve for 'J'. This gives,

J=40\times 0.2\\J=8\ N\cdot s

Therefore, the magnitude of impulsive force is 8 N.s.

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A cylindrical region of radius R contains a uniform magnetic field parallel to its axis. The field is zero outside the cylinder.
PtichkaEL [24]

The magnitude of the induced electric field is (RdB/dt)/4

The induced electric field is gotten from

-∫E.dl = dФ/dt where E = induced electric field, dl = path length vector, Ф = magnetic flux through cylindrical region = AB where A = area of magnetic flux = πR² where R = radius of cylindrical region and B = magnetic field.

So, -∫E.dl = dФ/dt

-∫E.dl = dAB/dt

-∫Edlcos0 = AdB/dt (where E.dl = Edlcos0 = Edl since E and dl are parallel to each other.)

So -∫Edl = πR²dB/dt

-E∫dl = πR²dB/dt (∫dl = 2πr since the integral is the circumference of the path)

-E(2πr) = πR²dB/dt (we integrate dl from r = 0 to 2R)

-E2π(2R - 0) = πR²dB/dt

-E4πR= πR²dB/dt

E = πR²dB/dt ÷ 4πR

E = -(RdB/dt)/4

So, the magnitude of the induced electric field is (RdB/dt)/4

Learn more about induced electric field here:

brainly.com/question/15730392

3 0
2 years ago
A. Besides protons, what other particles make up an atom? Write 2 - 3 sentences identifying the attractive force acts between a
Vinil7 [7]

Electric force is present between proton and electron of an atom.

<h3>What is the attractive force present between a proton and electron?</h3>

The attractive force between the electrons and the proton of the nucleus is called the electric force. This force attract electron towards the nucleus so that it can't escape from the atom easily so this force is very important for the atom.

<h3>How an atom of this element changes when it forms an ionic bond?</h3>

An atom of this element changes when it forms an ionic bond because the number of electron decreases due to losing of electron in order to get stability. We know that ionic bond forms between atoms when electron is lost or gain by the atom.

So we can conclude that electric force is present between proton and electron of an atom.

Learn more about force here: brainly.com/question/12970081

#SPJ1

6 0
1 year ago
A student in an undergraduate physics lab is studying Archimede's principle of bouyancy. The student is given a brass cylinder a
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Answer:

V = 0.3724 m³

T = 27.836 N

Explanation:

Given :

m = 3.21 kg  , W= 3.21 * 9.81 m / s² = 31.4901 N

ρ = 8.62 g / cm ³  = 8620 kg / m³

V = m / ρ =  3.21 kg  /  8620 kg / m³

V = 0.3724 m³

when submerged the weight of brass cylinder is equal to the tension in string:

F =  (0.3724m³) * (1000 kg / m³) * (9.81 m/s²²) = 3.653 ≈ 3.65 N

T = 31.4901 N - 3.65 N  

T = 27.836 N

3 0
3 years ago
The rocky planets are made of material that is much (mire/less) dense than the outer planets.​
IRINA_888 [86]

The outer planets (Jupiter, Saturn, Uranus, Neptune) are called the "<u>GAS</u> giants".

The rocky planets are called "rocky" because they're made of <u>ROCK</u>.

Does this help guide you to the correct choice ?

Here's another hint:  The MOST dense planet in our solar system, the one we call "Earth", is one of the 'rocky planets'.

7 0
3 years ago
Buoyancy is a force that always acts in an
Margarita [4]

Buoyancy is a force that always acts in an upward direction exerted by a fluid on a body placed in the fluid

Hope this helps :)

7 0
3 years ago
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