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Gwar [14]
3 years ago
10

A hockey player makes a slap shot exerting a constant force of 40.0 newtons on the puck for .2 seconds. What is the magnitude of

the impulse given to the puck?
Physics
1 answer:
Taya2010 [7]3 years ago
6 0

Answer:

Magnitude of impulsive force is <u>8 N.s</u>.

Explanation:

Given:

Force acting on the puck is, F=40.0\ N

Time interval for which the force acts is, \Delta t=0.2\ s

We are asked to find the impulsive force.

Impulsive force acting on a body is the sudden change in the momentum of the body due to the application of a large constant force for a very small interval of time.

Here, the hockey player applies a large force of 40 N for a very short interval of time. So, the impact on the puck is measured as Impulse and is represented by 'J'.

Impulse in terms of applied force and time interval is given as:

J=F\Delta t

Plug in the given values and solve for 'J'. This gives,

J=40\times 0.2\\J=8\ N\cdot s

Therefore, the magnitude of impulsive force is 8 N.s.

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-- Its average speed during that 30 sec is  (1/2) (0 + 240) = 120 m/s

-- Distance covered in 30 sec at an average speed of 120 m/s 

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The formula that has all of this in it is the formula for 
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       Distance = (1/2) · (acceleration) · (time)²

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When you translate these numbers into units for which
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When the light turns green, Andy mashes the pedal to the metal
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By accelerating at 8 m/s².  That's about 0.82 G  !

He does zero to 60 mph in 3.4 seconds, and at the end
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He doesn't need to worry about getting a speeding ticket.
Police cars and helicopters can't go that fast, and his local
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When I went through with the math, the answer I came upon was: 
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<span>Here is how I did it: First of all we need to know the equation. </span>

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