Answer:
The option is B is not true for Hubble telescope.
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From an energy balance, we can use this formula to solve for the angular speed of the chimney
ω^2 = 3g / h sin θ
Substituting the given values:
ω^2 = 3 (9.81) / 53.2 sin 34.1
ω^2 = 0.987 /s
The formula for radial acceleration is:
a = rω^2
So,
a = 53.2 (0.987) = 52.494 /s^2
The linear velocity is:
v^2 = ar
v^2 = 52.949 (53.2) = 2816.887
The tangential acceleration is:
a = r v^2
a = 53.2 (2816.887)
a = 149858.378 m/s^2
If the tangential acceleration is equal to g:
g = r^2 3g / sin θ
Solving for θ
θ = 67°
Answer:
C True. they rise and fall in a circular motion
Explanation:
The movement of water waves in the sea is described by a simple harmonic movement where the water droplets, which are the material particles of the movement oscillate up and down and the wave that is the energy of the movement travels perpendicular to it.
With this let's review the claims
A False
B False
C True.
D False
