All categories

3 years ago

Write a balanced chemical equation for the decomposition of solid sodium sulfide in aqueous solution.

Physics

2 answers:

Ganezh [65]3 years ago

7 0

Answer:

Na2S(s) → 2Na+(aq) + S2-(aq) is the only one that balances the reactants and the products.

Explanation:

lilavasa [31]3 years ago

3 0

The answer is Na2(s)→2Na+(aq)+S²-(aq)

You might be interested in

Please do this . will mark as brainlest;)

Vika [28.1K]

Answer:

no, not all three contains iron

no, not all three also contain magnets

Explanation:

a has the magnet

b and c have pieces of iron

4 0

3 years ago

After your school's team wins the regional championship, students go to the dorm roof and start setting off fireworks rockets. T

Ugo [173]

Answer:

the distance is 315.3696 m

Explanation:

The computation of the distance is given below:

Given that

Sound intensity = 1.67 × 10^-6 W/m^2

And, the distance = 233 m

Now as we know that

Power = Intensity × surface area

1.67 × 10^-6 × 4π(233)^2 = 1.67 × 10^-6 ÷ 2× 4π × d^2

d^2 = 2 × (223)^2

= √2 × 223

= 315.3696 m

Hence, the distance is 315.3696 m

5 0

3 years ago

Heat is also called

Mrac [35]

Thermal energy (any word that begins with therm has to do with heat)

6 0

3 years ago

Read 2 more answers

Check all of the following statements which are true. (You may need to consult Section 7.6 in the textbook.) You should check an

IrinaVladis [17]

Answer:

Explanation:

8 0

4 years ago

An unstable atomic nucleus of mass 1.58 10-26 kg initially at rest disintegrates into three particles. One of the particles, of

lara31 [8.8K]

Answer:

a The velocity of the third particle is $v_3 = (-15.629*10^{6}i -14.45*10^{6}j)\ m/s$

b The total kinetic energy increase $E = 6.50 *10^{-13} J$

Explanation:

To solve this question we are going to be using the concept of conservation of momentum which is mathematically represented as

$m_1v_1 +m_2v_2 +m_3v_3 = 0$

From the question

Mass of unstable atomic nucleus $m_0= 1.58 *10^{-26} kg$

Mass of x-axis particle $m_1 = 8.44* 10^{-27} kg$

Velocity of x-axis particle $v_ 1 = 4.00* 10^6 m/s$

Mass of y-axis particle $m_2 =5.20* 10^{-27} kg$

Velocity of y-axis particle $v_2 = 6.00 *10^6 m/s$

Since the initial mass is known we can obtain the mass of the third particle

Using the conservation of mass mathematical expression

$m_3 = m_0 - (m_1 +m_2)$

$m_3 = 1.58 *10^{-26} - ( 8.44* 10^{-27} + 5.20* 10^-27)$

$= 2.16 *10 ^{-27}kg$

Using the mathematical expression above for conservation of momentum

$(8.44 * 10^{-27})( 4.00* 10^6i) + (5.20 *10^{-27})(6.00* 10^6j) +(2.16*0^{-27})v_3 =0$

$v_3 = (-15.629*10^{6}i -14.45*10^{6}j)\ m/s$

The above is the vector solution now to obtain the value in numeric form we evaluate the magnitude of the vector

$Mag = \sqrt{(15.629*10^6)^2 +(14.45*10^6)^2}$

$= 21.285*10^6 \ m/s$

To obtain the total increase in kinetic energy which is mathematically represented as

$E = \frac{1}{2}m_1v_1 + \frac{1}{2}m_2v_2 + \frac{1}{2} m_3 v_3$

$E =\frac{1}{2} [(5.20*10^{-27})(6.0*0^{6})^2 + (8.44*10^{-27})(4.00*10^6)^2+\\\\(2.16*10^{-27})(21.285*10^6)^2]$

$= 6.50 *10^{-13} J$

5 0

3 years ago