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3 years ago

Calculate the volume of this regular solid.

Physics

2 answers:

lianna [129]3 years ago

6 0

Answer:

hes wrong its (653.45)

Explanation:

cause i got it wrong

-Dominant- [34]3 years ago

3 0

Answer:

The volume of the cylinder is approximately 653 cm.

Explanation:

The formula for the volume of a cylinder is V= (π)(r^2)(h).

All you would have to do is plug in the numbers.

V= ?, r= 4 cm, and h= 13 cm

V= (π)(4^2)(13)

The volume of the cylinder is approximately 653 cm.

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Two uniform, solid cylinders of radius R and total mass M are connected along their common axis by a short, light rod and rest o

sveta [45]

Explanation:

A) To prove the motion of the center of mass of the cylinders is simple harmonic:

System diagram for given situation is shown in attached Fig. 1

We can prove the motion of the center of mass of the cylinders is simple harmonic if

$a_{x} = -\omega^{2} x$

where aₓ is acceleration when attached cylinders move in horizontal direction:

<h3>PROOF:</h3>

rotational inertia for cylinders is given as:

$I=\frac{1}{2}MR^{2}$ -----(1)

Newton's second law for angular motion is:

∑τ = Iα ------(2)

For linear motion in horizontal direction it is:

∑Fₓ = Maₓ ------ (3)

By definition of torque:

τ = RF --------(4)

Put (4) and (1) in (2)

$RF=\frac{1}{2}MR^{2}\alpha$

from Fig 3 it can be seen that fs is force by which the cylinders roll without slipping as they oscillate

So above equation becomes

$f_{s}=\frac{1}{2}MR\alpha$ ------ (5)

As angular acceleration is related to linear by:

$a= R\alpha$

Eq (5) becomes

$f_{s}=\frac{1}{2}Ma_{x}$ ---- (6)

aₓ shows displacement in horizontal direction

From (3)

∑Fₓ = Maₓ

Fₓ is sum of fs and restoring force that spring exerts:

$\sum F_{x} = f_{s} - kx$ ----(7)

Put (7) in (3)

$f_{s} - kx = Ma_{x}$ [/tex] -----(8)

Using (6) in (8)

$\frac{1}{2}Ma_{x} - kx =Ma_{x}$

$a_{x} = \frac{2k}{3M} x$ --- (9)

For spring mass system

$a= -\omega^{2} x$ ----- (10)

Equating (9) and (10)

$\omega^{2} = \frac{2k}{3M}$

$\omega = \sqrt{ \frac{2k}{3M}}$

then (9) becomes

$a_{x} = - \omega^{2}x$

(The minus sign says that x and aₓ have opposite directions as shown in fig 3)

This proves that the motion of the center of mass of the cylinders is simple harmonic.

<h3 /><h3>B) Time Period</h3>

Time period is related to angular frequency as:

$T=\frac{2\pi }{\omega}$

$T = 2\pi \sqrt{\frac{3M}{2k}$

5 0

3 years ago

Describe a situation in which you can accelerate even though your speed doesn’t change.

KATRIN_1 [288]

Acceleration is not the same as speeding up. It refers to any modification of motion's direction or speed. Accelerated motion is any movement that is not constant speed in a straight line.

<h3>What is meant by acceleration?</h3>

The rate at which an object's velocity for time changes is referred to as acceleration in mechanics. They are vector quantities and accelerations. The direction of the net force acting on an object determines the direction of its acceleration.

An object's velocity can alter depending on whether it moves faster or slower or in a different direction. A falling apple, the moon orbiting the earth, and a car stopped at a stop sign are a few instances of acceleration.

The rate at which velocity changes is called acceleration. Acceleration typically indicates a change in speed, but not necessarily. An item that follows a circular course while maintaining a constant speed is still moving forward because the direction of its motion is shifting.

To learn more about acceleration refer to:

brainly.com/question/605631

#SPJ4

6 0

2 years ago

A prism of angle 60° is of a material of refractive index √√2. Calculate angles of minimum deviation and maximum deviation.

Tom [10]

Answer:

i don't know if this helps but The refractive index of the material of the prism of an angle 60 degree is 1.62 for sodium light. there you go hope it helps

Explanation:

5 0

2 years ago

A car of mass m accelerates from speed v_1 to speed v_2 while going up a slope that makes an angle theta with the horizontal. Th

Karo-lina-s [1.5K]

Answer:

Work done by external force is given as

$Work_{external} = mgLsin\theta + \mu mgLcos(\theta) + \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2$