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Dahasolnce [82]
3 years ago
12

Calculate the volume of this regular solid.

Physics
2 answers:
lianna [129]3 years ago
6 0

Answer:

hes wrong its (653.45)

Explanation:

cause i got it wrong

-Dominant- [34]3 years ago
3 0

Answer:

The volume of the cylinder is approximately 653 cm.

Explanation:

The formula for the volume of a cylinder is V= (π)(r^2)(h).

All you would have to do is plug in the numbers.

V= ?, r= 4 cm, and h= 13 cm

V= (π)(4^2)(13)

The volume of the cylinder is approximately 653 cm.

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I have no idea what to do. Plz help!
aleksklad [387]
Work is (force) times (distance). For Amy, you know both of them, and you can easily multiply them to find the amount of work. For Joe, the distance is zero, which should tell you all you need to know.
7 0
2 years ago
3. Neha travels 4 m towards the north, 3m towards the east, and then 7 m towards south, find the displacement and total distance
Digiron [165]

Answer:

Explanation:

Explanation: total displacement =3√2m. and total distance covered=14m. I hope this is right and helps u.

7 0
3 years ago
What requirement must a force acting on a object satisfy in order for the object to undergo simple harmonic motion?
viktelen [127]

Answer:

Simple harmonic motion is the movement of a body or an object to and from an equilibrium position. In a simple harmonic motion, the maximum displacement (also called the amplitude) on one side of the equilibrium position is equal to the maximum displacement.

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6 0
2 years ago
Vector A has a magnitude of 30 units. Vector B is perpendicular to vector Aand has a magnitude of 40 units. What would the magni
Fudgin [204]

Answer:

|\vec A + \vec B| = 50 units

Explanation:

As we know that magnitude of two vectors is given as

|\vec A + \vec B| = \sqrt{A^2 + B^2 + 2AB cos\theta}

here we know that

A = magnitude of vector A

B = magnitude of vector B

\theta = angle between two vectors

so here we know that

A = 30 units

B = 40 units

angle = 90 degree

so we have

|\vec A + \vec B| = \sqrt{30^2 + 40^2 + 2(30)(40)cos90}

|\vec A + \vec B| = \sqrt{30^2 + 40^2}

|\vec A + \vec B| = 50 units

3 0
2 years ago
Please help me, this is a physics test.
sweet-ann [11.9K]

Answer:

a = 2 [m/s²]

Explanation:

To be able to solve this problem we must make it clear that the starting point when the time is equal to zero, the velocity is 5 [m/s] and when three seconds have passed the velocity is 11 [m/s], this point is the final point or the final velocity.

We can use the following equation.

v_{f}=v_{o}+a*t\\

where:

Vf = final velocity = 11 [m/s]

Vo = initial velocity = 5 [m/s]

a = acceleration [m/s²]

t = time = 3 [s]

11 = 5 + a*3\\6=3*a\\a= 2[m/s^{2} ]

4 0
2 years ago
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