All categories

2 years ago

Explain why a basketball doesn’t bounce the same height each time you drop it.

Physics

2 answers:

nekit [7.7K]2 years ago

7 0

Hi!

So if you drop a basketball from a higher height, it has more time to gather more energy, which it then forces against the ground and causes the ball to bounce.

Hope this helps! Sorry I didn't really use any technical terms!

DIA [1.3K]2 years ago

3 0

The basketball do not bounce back to the same height after each drop due to the fact of loss of kinetic energy.

<u>Explanation: </u>

When the basketball or any ball is dropped off from a certain height it falls down under the influence of gravity with the kinetic energy which has been transferred to the ball with hand by dribble.

When the basketball hits the ground with the kinetic energy, it loses some of the energy to the ground and then with the action reaction pair with the ground, is bounced back but with lower energy to a lower height.

You might be interested in

A guyot is ________. A. any portion of the ocean floor that is topographically higher than surrounding sea floor B. an extinct o

Maksim231197 [3]

Answer:

c.an extinct oceanic hot-spot volcano that has subsided below sea level

Explanation:

- Marine geology defines a guyot as an isolated underwater volcanic mountain with a flat top more than 200m below the surface of the sea.

-The flat top is due to years of wave erosion.

-Guyots can form a chain of seamounts as the ocean plate of the Earth's crust moves slowly over a hot spot that remains stationary beneath the plate.

6 0

2 years ago

Which planet has the most extreme temperature variations

vichka [17]

Answer:

I believe Mercury has the most extreme temperatures in the solar system, ranging from -280?F at night to 800 degrees F during the day for parts of the surface.

Hope that helps! :)

5 0

2 years ago

Read 2 more answers

Which shows the conversion of 2.09 × 10-4 meters to millimeters?

Ivenika [448]

I think its A I hope this help thank you!!

4 0

2 years ago

A cylindrical capacitor has an inner conductor of radius 2.7 mmmm and an outer conductor of radius 3.1 mmmm. The two conductors

Mars2501 [29]

Answer:

(A) Capacitance per unit length = $4.02 \times 10^{-10}$

(B) The magnitude of charge on both conductor is $Q = 4.22 \times 10^{-19}$ C and the sign of charge on inner conductor is $+Q$ and the sign on outer conductor is $-Q$

Explanation:

Given :

Radius of inner part of conductor $(R_{1})$ = $2.7 \times 10^{-3}$ m

Radius of outer part of conductor $(R_{2})$ = $3.1 \times 10^{-3}$ m

The length of the capacitor $(l)$ = $3 \times 10^{-3}$ m

(A)

Capacitance is purely geometrical property. It depends only on length, radius of conductor.

From the formula of cylindrical capacitor,

$C = \frac{2\pi\epsilon_{o} l }{ln\frac{R_{2} }{R_{1} } }$

Where, $\epsilon_{o} = 8.85 \times 10^{-12}$

But we need capacitance per unit length so,

$\frac{C}{l} = \frac{2\pi\epsilon_{o} }{ln\frac{R_{2} }{R_{1} } }$

capacitance per unit length = $\frac{6.28 \times 8.85 \times 10^{-12} }{ln(1.148)} = 4.02 \times 10^{-10}$

(B)

The charge on both conductors is given by,

$Q = C \Delta V$

Where, C = capacitance of cylindrical capacitor and value of $C = 12.06 \times 10^{-13}$ F, $\Delta V = 350 \times 10^{-3}$ V

∴ $Q = 4.22 \times 10^{-19}$ C

The magnitude of charge on both conductor is same as above but the sign of charge is different.

Charge on inner conductor is $+Q$ and Charge on outer conductor is $-Q$ .

8 0

3 years ago

I have no idea what to do. Plz help!

aleksklad [387]

Work is (force) times (distance). For Amy, you know both of them, and you can easily multiply them to find the amount of work. For Joe, the distance is zero, which should tell you all you need to know.

7 0

2 years ago