The duration (i.e time) of the impact, given that the head impact was 1770 N is 0.005 s
<h3>How do I determine the duration (i.e time)?</h3>
Impulse is defined as the change in momentum of an object. It is expressed as:
Impulse = change in momentum
Impulse = final momentum – Initial momentum
Impule = m(v - u)
Impulse = force × time
Impulse = Ft
Thus,
Ft = m(v - u)
Where
- F is the force
- t is the time
- m is the mass
- u is the initial velocity
- v is the final velocity
Now, we can obtain the duration (i.e time) of the impact. Details below:
- Force (F) = 1770 N
- Initial velocity = 2.09 m/s
- Mass (m) = 4.12 Kg
- Final velocity = 0 m/s
- Duration (t) =?
Ft = m(v + u) since the collision came to a stop
1770 × t = 4.12 × (0 + 2.09)
1770 × t = 4.12 × 2.09
Divide both sides by 1770
t = (4.12 × 2.09) / 1770
t = 0.005 s
Thus, the duration is 0.005 s
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Answer:
The gain in velocity is 0.37m/s
Explanation:
We need solve this problem though the conservation of momentum. That is,
Using the equation to find 
,
Using the conservation of energy equation, we have,
Now this energy over the cannonball
The gain in velocity is 0.37m/s
The air pressure inside the balloon increases as the number of particles increases.
Answer:
Explanation:
= Force on one side of the door by first waiter = 257 N
= Force on other side of the door by second waiter
= distance of first force by first waiter from hinge = 0.567 m
= distance of second force by second waiter from hinge = 0.529 m
Since the door does not move. hence the door is in equilibrium
Using equilibrium of torque by force applied by each waiter
