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Mashutka [201]
3 years ago
7

Explain why a basketball doesn’t bounce the same height each time you drop it.

Physics
2 answers:
nekit [7.7K]3 years ago
7 0

Hi!

So if you drop a basketball from a higher height, it has more time to gather more energy, which it then forces against the ground and causes the ball to bounce.

Hope this helps! Sorry I didn't really use any technical terms!

DIA [1.3K]3 years ago
3 0

The basketball do not bounce back to the same height after each drop due to the fact of loss of kinetic energy.

<u>Explanation: </u>

When the basketball or any ball is dropped off from a certain height it falls down under the influence of gravity with the kinetic energy which has been transferred to the ball with hand by dribble.

When the basketball hits the ground with the kinetic energy, it loses some of the energy to the ground and then with the action reaction pair with the ground, is bounced back but with lower energy to a lower height.

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repal postive to postive or negitve to negtive

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Calculate the formal charge on the indicated atom in each of the following molecules or ions. Some molecules may have more than
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Answer:

Formal charge for the first resonance structure of NO₂; first Oxygen = 0, N = +1, second Oxygen = -1

Formal charge for the second resonance structure of NO₂; first Oxygen = -1, N = +1, second Oxygen = 0

Explanation:

The formal charge of an atom in a molecule is the assumed charge the atom would have if the electrons in the bonds are redistributed evenly between the atoms.

Formal charge = valence electrons - (non-bonding electrons) - (bonding electrons / 2).

For NO₂ molecule, the formal charges for the atoms are as follows;

First Oxygen atom = 6 - 4 - 4/2 = 0

For Nitrogen = 5 - 1 - 6/2 = +1

For the second Oxygen atom = 6 - 6 - 2/2 = -1.

Overall charge = 0 + (+1) + (-1) = 0

For the second resonance structure,

First Oxygen atom = 6 - 6 - 2/2 = -1

For Nitrogen = 5 - 1 - 6/2 = +1

For the second Oxygen atom =  6 - 4 - 4/2 = 0

Overall charge = (-1) + (+1) + (0) = 0

Note: Where resonance structures for atoms or ions exist, the formal charges of each of the respective atoms or ions are calculated according.

8 0
3 years ago
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A ball is dropped from somewhere above a window that is 2.00 m in height. As it falls, it is visible to a person boxing through
Irina18 [472]

Answer:

4.14 m

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In the last leg of the journey the ball covers 2 m in 2ms or 0.2 s .

Let in this last leg , u be the initial velocity.

s = ut + 1/2 g t²

2 = .2 u + .5 x 9.8 x .04

u = 9.02 m /s .

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v² = (9.02)² + 2 x 9.8 x 2

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v = 10.97 m / s

Now consider the whole height from where the ball dropped . Let it be h.

Initial velocity u = 0

v² = u² +2gh

(10.97 )² = 2 x 9.8 h

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Height from window

= 6.14 - 2m

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4 years ago
A mass of 0.560 kg is attached to a spring and set into oscillation on a horizontal frictionless surface. The simple harmonic mo
Slav-nsk [51]

Answer:

(a) A = 0.700m

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Answer:

a. at either A or B

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At point A and B, the velocity of the object becomes zero and hence the kinetic energy of a body varies directly proportional to its velocity.

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