Question

How many moles of ideal iodine gas has a volume of 1250 mL at 10 degrees C and 768 mm pressure?

Answer 1

Answer:

$n=0.0564mol$

Explanation:

Hello,

In this case, since iodine is ideal we can use the ideal gas equation to compute the moles at the given conditions, considering the following units:

$V=1250mL*\frac{1L}{1000mL} =1.25L\\P=768mmHg*\frac{1atm}{760mmHg}=1.01atm\\ T=10+273.15=283.15K$

$PV=nRT$

$n=\frac{PV}{RT} =\frac{1.01atm*1.25L}{0.082\frac{atm*L}{mol*K}*273.15K} \\\\n=0.0564mol$

Best regards.