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3 years ago

Which is FALSE regarding how elements with the same number of valence electrons will be similar?

1 answer:

8 0

Elements with the same number of electrons or the same electronic configuration in the valence shell are observed to be within the same group in the periodic table. The groups are columns in in the periodic table. The elements only have the same charges when they occur as an ion. That is their only similarity apart from being metals or nonmetals. Examples would be elements in Group 1A like Na, Li, K, Rb and Cs.

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How many moles of oxygen are in 3.0 moles c6h12o6 ? Help!!

In-s [12.5K]

1 mole C₆H₁₂O₆ ------------- 6 moles oxygen
3 moles C₆H₁₂O₆ ----------- X
X = (3×6)/1
X = 18 moles

:)

3 0

4 years ago

Read 2 more answers

Light is released when an excited electron moves from higher energy level back down to its lower, more stable energy level. The

kolbaska11 [484]

A0 emission as there is an increase in energy

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3 years ago

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A solution is made by mixing of water and of acetic acid . Calculate the mole fraction of water in this solution. Be sure your a

Molodets [167]

Answer:

The answer is "0.35".

Explanation:

please find the complete question in the attached file.

Mass of $CH_3C0_2 H$ $= 77 \ g \\\\$

Molar mass of $CH_3C0_2 H$ $= 60.05 \ \frac{g}{mol} \\\\$

No of moles in $n_{CH_3CO_2H}$ $= 77 \ g \times \frac{1 \ mol \ CH_3C0_2H}{60.05 \ g}$

$= 1.28 \ mol \ CH_3CO_2H$

Mass of water $(H_2O)$ $= 42 \ g$

The molar mass of water $(H_2O)$ $= 18.02 \ \frac{g}{mol}$

moles of water $n_{H_2O}$ :

$= 42 \ g \times \frac{1 mol H_2O}{18.02 \ g} \\\\= 2.33 \ mol \ H_2 O$

Molfraction of acetic acid:

$X CH_2CO_2H = \frac{n_{CH_3CO_2H}}{n_CH_3CO_2H +n_{H_2}}\\\\$

$=\frac{1.28 \ mol}{1.28 \ mo1 + 2.33 mol}\\\\ = 0.354\\\\= 0.35$

7 0

3 years ago

Force can be added together

Zepler [3.9K]

Forces can be added only when they both are going in the same direction as 2n +2n = 4n of force in the same direction if they are 2 facing forces they would have had to be subtracted, which ever force is greater that will be the momentum of the force.

Hope this helps.

7 0

3 years ago

Choose the molecule(s) that will only show two signals, with an integration ratio of 2:3, in their 1H NMR spectrum.

mrs_skeptik [129]

The question is missing the molecules in which the integration ratio of 2:3 will be observed. The complete question is given in the attachment.

Answer:

Molecule (a), (c), and (f) will show two peaks with the integration ratio of 2:3 in their 1H NMR spectrum

Explanation:

In the 1H NMR spectrum, the peak area is dependent on the number of hydrogen in a specific chemical environment. Hence, the ratio of the integration of these signals provides us with the relative number of hydrogen in two peaks. This rationale is used for the assignment of molecules that will give 2:3 integration ratio in the given problem.

Molecule (a) have two CH₂ and three CH₃ groups. Hence, it will give two peaks and their integration ratio becomes 2:3 (Answer)
Molecule (b) contains three chemical environments for its hydrogen atoms
Molecule (c) have a single CH₂ and CH₃ group giving integration ratio of 2:3 (Answer)
Molecule (d) will give two peaks but their ratio will be 1:3 because of two hydrogens of CH₂ and six hydrogens from two CH₃ groups
Molecule (e) have three CH and three CH₃ groups, so their ratio will become 1:3
Molecule (f) contains four CH and two CH₃ groups, giving two peaks. So, the integration ratio of their peaks is 2:3 (Answer)
Molecules
(g)
and
(h)
both have two CH and two CH₃ groups giving two peaks with the integration ratio of 1:3

3 0

4 years ago