Answer:
Mass = 90.28 g
Explanation:
Given data:
Mass of Ca(OH)₂ = ?
Volume of solution= 1.5 L
Molarity of solution = 0.81 M
Solution:
First of all we will calculate number of moles.
Molarity = number of moles / volume in L
by putting values,
0.81 M = Number of moles / 1.5 L
Number of moles = 0.81 M × 1.5 L
Number of moles = 1.22 mol
Mass of Ca(OH)₂ in gram:
Mass = number of moles × molar mass
Mass = 1.22 mol × 74.09 g/mol
Mass = 90.28 g
Mass = 5.90 x 114 = 672.6g.
This can be rounded to <em>673g</em>
<em>C = 12 grams x 8 = 96 grams </em>
<em>H = 1 gram x 18 = 18 grams </em>
<em>Total = 96 + 18 = 114 grams in one mole. </em>
<u>If you have 5.9 moles, multiply this by the weight of one mole (114 grams) = 672.6 rounded to 673 grams in 5.9 moles. </u>
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