Answer:
c. Norms.
Explanation:
When Elena noticed her friend getting uncomfortable when she kisses him on the cheeks as a form of greeting she was violating his norms.
Norms are something that is standard or typical.
In USA there they not used to kiss on the cheeks to greet their friends there would be some other norm of greeting someone.
Answer:
filter the data
Explanation:
its like when you filter a search on y o u t u b e and say u search among us u can filter and say live vids or channel's
Answer:
The probability that among three randomly selected Internet users, at least one is more careful about personal information when using a public Wi-Fi hotspot is 0.964
If the survey subjects <em>volunteered</em> to respond , then those with the strongest opinions are most likely respond. The survey sample is then not randomly selected, the survey may have a <em>response bias.</em>
Explanation:
Let P(at least one is more careful about personal information when using a public Wi-Fi hotspot) denote the probability that among three randomly selected Internet users, at least one is more careful about personal information when using a public Wi-Fi hotspot, then we have the equation
P(at least one is more careful about personal information when using a public Wi-Fi hotspot) = 1 - P(none of the selected users is more careful about personal information when using a public Wi-Fi hotspot)
- If 67% of Internet users are more careful about personal information when using a public Wi-Fi, then 33% of them are not.
P(none of the selected users is more careful about personal information when using a public Wi-Fi hotspot) =
≈ 0.036
P(at least one is more careful about personal information when using a public Wi-Fi hotspot) = 1 - 0.036 = 0.964
Answer:
Point, Line, Shape,Form, Color, Value, and Texture.
Explanation:
The elements of design, are the building blocks used by the designers to create the designs. ...
Point, Line, Shape,Form, Color, Value, and Texture.
Answer:
2^11
Explanation:
Physical Memory Size = 32 KB = 32 x 2^10 B
Virtual Address space = 216 B
Page size is always equal to frame size.
Page size = 16 B. Therefore, Frame size = 16 B
If there is a restriction, the number of bits is calculated like this:
number of page entries = 2^[log2(physical memory size) - log2(n bit machine)]
where
physical memory size = 32KB which is the restriction
n bit machine = frame size = 16
Hence, we have page entries = 2^[log2(32*2^10) - log2(16)] = 2ˆ[15 - 4 ] = 2ˆ11