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3 years ago

Please help!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

dezoksy [38]3 years ago

7 0

100÷30 ? (correct me if I'm wrong) or 90÷30

otez555 [7]3 years ago

4 0

Stupid boy hdheduhyj8iuhh

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Would it be B? Let me know

IgorC [24]

Answer:

whats the question?

Step-by-step explanation:

8 0

3 years ago

How many solutions does the equation 6x-10=2(3x+8) have?

ivanzaharov [21]

Answer:

No solution

Step-by-step explanation:

As 6x on lhs and 2×3x on the rhs are equal and cancel each other

6 0

3 years ago

Factor 16x^2 + 49. Check your work.

Shtirlitz [24]

Answer:

$16x^2+49=(x-\frac{7i}{4})(x+\frac{7i}{4})$

Step-by-step explanation:

Given : Expression $16x^2+49$

To find : Factor the expression ?

Solution :

The given expression is a quadratic function $y=ax^2+bx+c$ the solution is $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

On comparing with general form,

a=16, b=0, c=49

Substitute in the formula,

$x=\frac{-0\pm\sqrt{0^2-4(16)(49)}}{2(16)}$

$x=\frac{\pm\sqrt{-3136}}{32}$

$x=\frac{\pm56i}{32}$

$x=\frac{56i}{32},\frac{-56i}{32}$

$x=\frac{7i}{4},\frac{-7i}{4}$

Factors are $(x-\frac{7i}{4}),(x+\frac{7i}{4})$

Therefore, $16x^2+49=(x-\frac{7i}{4})(x+\frac{7i}{4})$

4 0

3 years ago

The Japanese 5 yen coin has a hole in the middle. If the diameter of the coin is 22 mm and the diameter of the hole is 5 mm, how

Yanka [14]

Answer:

4.4mm

Step-by-step explanation:

Circumference of circle

2 Pi r

Diameter of coin = 22mm

Therefore the radius = 11mm

Therfroe the outer edge (circumference)

= 2 Pi r

= 2 x Pi x 11

=69.11mm

For the inner edge

Diameter = 5

Radius = 2.5

Therefroe inner edge (circumference)

= 2 Pi r

= 2 x Pi x 2.5

= 15.7mm

The difference is

69.11 - 15.7

=4.4mm

7 0

3 years ago

What is the mass of a 15cm cube of lron if density of iron is 78grams/cm

amm1812

Answer:

M = 1170 g

Step-by-step explanation:

Mass = density × volume

M = p x v

M = 78 x 15

M = 1170 g

3 0

3 years ago

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