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Alchen [17]
3 years ago
7

What do u need to know to describe the velocity of an object?

Chemistry
2 answers:
Alex_Xolod [135]3 years ago
5 0
To determine the velocity of an object, you need to know the displacement and the change in time. 

v = displacement / change in time

Svet_ta [14]3 years ago
5 0
To describe it you need to know to rate of change of position.
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THIS NOT MY WORK. its for my sister. HELP HER
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Answer:

Your answer will be b(molten material from the outer core makes its way to the surface of earth)

Explanation:

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It would be nice if someone HELPED. During an experiment, you observe that two charged balloons repel each other. When you bring
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They are similarly charged, which is why they repel each other.

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How many water molecules (H2O) can be produced from 6 molecules of hydrogen gas (white) reacting with 6 molecules of oxygen gas
Vladimir79 [104]
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The raw water supply for a community contains 18 mg/L total particulate matter. It is to be treated by addition of 60 mg alum (A
s344n2d4d5 [400]

Solution :

Given :

The steady state flow = 8000 $ m^3 /d $

                                    $= 80 \times 10^5 \ I/d $

The concentration of the particulate matter = 18 mg/L

Therefore, the total quantity of a particulate matter in fluid $= 80 \times 10^5 \ I/d \times 18 \ mg/L $

$= 144 \times 10^6 \ mg/g$

$= 144 \ kg/d $

If 60 mg of alum $ [Al_2(SO_4)_3.14 H_2O] $ required for one litre of the water treatment.

So Alum required for  $ 80 \times 10^5 \ I/d $

$= 80 \times 15^5 \ I/d  \times 60 \ mg \ alum /L$

$= 480 \times 10^6 \ mg/d $

or 480 kg/d

Therefore the alum required is 480 kg/d

1 mg of the alum gives 0.234 mg alum precipitation, so 60 mg of alum will give $ = 60 \times 0.234 \text{ of alum ppt. per litre} $

      $= 14.04 $ mg of alum ppt. per litre

480 kg of alum will give = 480 x 0.234 kg/d

                                        = 112.32 kg/d ppt of alum

Daily total solid load is  $= 144 \ kg/d + 112.32 \ kg/d$

                                       = 256.32 kg/d

So, the total concentration of the suspended solid after alum addition $= 18 \ mg/L + 60 \times 0.234 $

= 32.04 mg/L

Therefore total alum requirement = 480 kg/d

b). Initial pH = 7.4

 The dissociation reaction of aluminium hydroxide as follows :

$Al(OH)_3 \rightleftharpoons Al^{3+} + 3OH^{-} $

After addition, the aluminium hydroxide pH of water will increase due to increase in $ OH^- $ ions.

Therefore, the pH of water will be acceptable range after the addition of aluminium hydroxide.

c). The reaction of $CO_2$ and water as follows :

$CO_2 (g) + H_2O (l) \rightarrow H_2CO_3$

For the atmospheric pressure :

$p_{CO_2} = 3.5 \times 10^{-4} \ atm $

And the pH is reduced into the range of 5.9 to 6.4

6 0
2 years ago
Define the SI unit fro length, mass time , and temperature
Julli [10]

Length=The distance between two points

Mass=The amount of matter contained in a body

Time=The interval or duration between two events

Temperature=The hotness and coldness of a body

7 0
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