Answer: nucleons
Explanation:
The nucleons are the particles that constitue the nuclei of the atoms. Those are protons and neutrons.
They are not elementary particles (quarks are the elementary particles that form both protons and neutrons).
Protons are the particles that define the elements. Any different elements have different number of protons. H has one proton, He has 2 protons, Li has three protons, Na has 11 protons, U has 92 protons.
Protons are positively charged and the number of protons in any neutral atom is equal to the number of electrons (the electrons, which are elementary negatively charged particles, are around the nucleous).
Neutrons have not charge and are responsible for the stability of the nuclei. They are fundamental to avoid that the repulsion forces between the positively charged protons ends causing the collapse of the nuclei.
The removal of trees would most likely decrease the amount of carbon in the atmosphere.
Please note that it is useful to add the options provided with the question, in order to get a most accurate answer and have your question answered quicker.
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Answer: (C) Vaporizing
Explanation:
Vaporization is the process in which the substance change the state of of liquid into the gas state.
The vaporization process require the largest input of the energy as when the state is in the solid state then, the solid substances contain the strong forces of the attraction and they require high energy to break these strong bonds.
For changing the liquid state into the gases state we require to overcome the surface tension and require enough energy for acquiring the vaporization state.
Therefore, option (C) is correct.
Answer:
Explanation:
Hello,
In this case, we write the reaction again:
In such a way, the first thing we do is to compute the reacting moles of lead (II) nitrate and potassium iodide, by using the concentration, volumes, densities and molar masses, 331.2 g/mol and 166.0 g/mol respectively:
Next, as lead (II) nitrate and potassium iodide are in a 1:2 molar ratio, 0.04635 mol of lead (II) nitrate will completely react with the following moles of potassium nitrate:
But we only have 0.07885 moles, for that reason KI is the limiting reactant, so we compute the yielded grams of lead (II) iodide, whose molar mass is 461.01 g/mol, by using their 2:1 molar ratio:
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