1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeka57 [31]
3 years ago
8

The earth is made up of?

Chemistry
1 answer:
ollegr [7]3 years ago
4 0

Answer:

The Earth is made out of many things❤✌✔

Explanation:

The Earth is made out of many things. Deep inside Earth, near its center, lies Earth's core which is mostly made up of nickel and iron. Above the core is Earth's mantle, which is made up of rock containing silicon, iron, magnesium, aluminum, oxygen and other minera

You might be interested in
Which of these is a chemical property?
Katyanochek1 [597]
Yes, refer to the previous answer.
6 0
3 years ago
Read 2 more answers
A toxicologist studying mustard gas, S(CH2CH2Cl)2, a blistering agent, prepares a mixture of 0.675 M SCl2and 0.973 M C2H4 and al
Musya8 [376]

Answer:

The value of K_p is 0.02495.

Explanation:

Initial concentration of SCL_2 gas = 0.675 M

Initial concentration of C_2H_4 gas = 0.973 M

Equilibrium concentration of mustard gas = 0.35 M

SCl_2 (g) + 2 C_2H_4 (g)\rightleftharpoons S(CH_2CH_2Cl)_2(g)

initially

0.675 M            0.973 M        0

At equilibrium ;

(0.675-0.35) M            (0.973-2 × 0.35) M        0.35 M

The equilibrium constant is given as :

K_c=\frac{[S(CH_2CH_2Cl)_2]}{[SCl_2][C_2H_4]^2}

=\frac{0.35 M}{(0.675-0.35) M\times ((0.973-2 × 0.35) M)^2}

K_c=14.45

The relation between K_p and K_c are :

K_p=K_c\times (RT)^{\Delta n}

where,

K_p = equilibrium constant at constant pressure = ?

K_c = equilibrium concentration constant =14.45

R = gas constant = 0.0821 L⋅atm/(K⋅mol)

T = temperature = 20.0°C =20.0 +273.15 K=293.15 K

\Delta n = change in the number of moles of gas = [(1) - (1 + 2)]=-2

Now put all the given values in the above relation, we get:

K_p=14.45\times (0.0821L.atm/K.mol\times 293.15 K)^{-2}

K_p=6.2\times 10^{4}

K_p=0.02495

The value of K_p is 0.02495.

7 0
2 years ago
Three 5-l flasks, fixed with pressure gauges and small valves, each contains 4 g of gas at 273 k. flask a contains h2, flask b c
Varvara68 [4.7K]
First, please check the missing part in your question in the attachment.
a) So first, the Rank of pressure:
according to this formula PV = nRT and when n = m/Mw
PV = m/Mw * R*T
when we have the same mass m and the same V volume so P will proportional with the mole weight M as when the M is smaller the pressure will be greater 
when Mw of H2(A) = 2 g / Mw of He (B) = 4 g and Mw of CH4(C) = 16 g
∴ Pressure :
 (A) > (B) > (c)

B) The rank of average molecular kinetic energy:
when K = 3/2 KB T
when K is the average kinetic energy per molecule of gas 
and KB is Boltzmann's constant
and T is the temperature (K)
So from this equation, we can know that K only depends on T value, and when we have the T constant here for A, B, and C So the rank of K will be like the following:
∴ A = B = C
C) the rank of diffusion rate after the valve is opened:
according to this formula:
R2/R1 = √M1/M2
from this equation, we can see that diffusion is proportional to the reciprocal of the molecular mass M so,
when Mw H2 (A) = 2 g & Mw He(B) = 4 g & CH4 (C) = 16 g
∴ the rank of diffusion:
A > B > C

D) The rank of the Total kinetic energy of the molecules:
when we have the Mw different so it will make the no.of molecules differs as when the Mw is low the no.of molecules will be hight, and when the average molecular kinetic energy equals. so the total kinetic energy will depend on no. of molecules 
∵ Mw A < Mw B < Mw C 
∴no .of molecules of A > B >C
∴ the rank of total kinetic energy is:
A > B > C

e) the rank of density:

when ρ = m/ v 
and m is the mass & v is the volume and we have both is the same for A, B, and C
so the density also will be the same, ∴ the rank of the density is:
A = B = C

F) the rank of the collision frequency:
as the no.of molecules increase the collision frequency increase and depend also on the velocity and it's here the same.
∴ Collision frequency will only depend on the no.of molecules
we have no.of molecules of A > B > C as Mw A < B < C 
∴the rank of the collision frequency is:
A > B > C 

 



7 0
2 years ago
A legal right to use the property owned by someone else in a specified manner is known as an?
gogolik [260]

Answer:

I believe as sharing bit

4 0
1 year ago
Read 2 more answers
Which formula correctly represents antinomy trichloride?<br> SnS2<br> SnCl3<br> SbCl2<br> SbCl3
max2010maxim [7]

Answer:

SbcI3

Explanation:

The symbol of antimony is 'Sb'.

The symbol of chlorine is 'Cl'

First write down the symbol of the first element.

Use the prefix to determine the atoms of first element. If there is no prefix on element then there is only 1 atom.

Now write down the symbol of the second element.

Use the prefix to determine the atoms of second element.

Use prefix as 'mono' for '1', 'di' for '2', 'tri' for '3' and so on.

3 0
2 years ago
Read 2 more answers
Other questions:
  • You have the same two resistors on a 10 volt series circuit. Will the voltage going into the second resistor be more, less, or t
    14·1 answer
  • A student reacts 20.0 mL of 0.248 M H2SO4 with 15.0 mL of 0.195 M NaOH. Write a balanced chemical equation to show this reaction
    6·1 answer
  • What is the value for ∆Soreaction for the following reaction, given the standard entropy values? Fe2O3(s) + 3H2(g) 2 Fe(s) + 3H2
    12·1 answer
  • What is the frequency of light for which the wavelength is 7.1 × 102 nm?
    13·1 answer
  • If an atom has 17 protons and 18 neutrons, what is the charge of the atom's nucleus?​
    15·1 answer
  • 2
    6·1 answer
  • Is hydrogen peroxide a element, compound or a mixture?
    14·1 answer
  • NEED HELP!
    11·1 answer
  • Oil spills are a very serious form of pollution. They severely affect marine biodiversity and coastal ecosystems. The table show
    6·2 answers
  • Select the correct answer.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!