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Marianna [84]
3 years ago
6

A student walked 2km in .5 hours what is his average speed on the way to school

Physics
1 answer:
ddd [48]3 years ago
5 0
Speed = Distance%Time

Speed is 0,4km/h


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The light from Barnard's Star takes about 5.94 years to reach Earth. Which of these statements is correct about Barnard's star?
s344n2d4d5 [400]

Answer:

It is located at a distance of 5.94 light years from Earth.

Explanation:

Since light transmitted from the star takes approximately 5.94 years to reach the earth, it means the star is  located at a distance of 5.94 light years from Earth.

7 0
3 years ago
A ball that is attached to a string travels in a horizontal, circular path, as shown in Figure 1. At time t0 , the ball has a sp
Levart [38]

Answer:

F₁ = 4 F₀

Explanation:

The force applied on the string by the ball attached to it, while in circular motion will be equal to the centripetal force. Therefore, at time t₀, the force on ball F₀ is given as:

F₀ = mv₀²/r   --------------- equation (1)

where,

F₀ = Force on string at t₀

m = mass of ball

v₀ = speed of ball at t₀

r = radius of circular path

Now, at time t₁:

v₁ = 2v₀

F₁ = mv₁²/r

F₁ = m(2v₀)²/r

F₁ = 4 mv₀²/r

using equation (1):

<u>F₁ = 4 F₀</u>

5 0
3 years ago
Potential energy can be converted into kinetic energy, a good example of this is when a pole-vaulter bends the pole during a lea
lesantik [10]

Answer:

The pole stores elastic potential energy when the pole is bent because its shape is change from its natural shape and it will want to go back to its original form, just like a spring or stretched elastic material.

Question:

Why did you lie about being in college?

6 0
3 years ago
Read 2 more answers
Melissa heated a few blue crystals in a test tube. After a few minutes, she observed that the crystals had turned white and a fi
seraphim [82]
I think it will be developed theory
4 0
3 years ago
The shortest pipe in a particular organ is 1.23 m.
AVprozaik [17]

Answer:

The 9th harmonic is 1,010.67 Hz.

Explanation:

Given;

length of the pipe, L = 1.23 m

speed of sound at 0°C = 331.5 m/s

A pipe closed at one end is known as a closed pipe;

The wavelength of the sound for the first harmonic is calculated as;

L = Node ------ > Antinode

L = \frac{\lambda }{4} \\\\\lambda = 4L

First harmonic:  F_0 = \frac{V}{\lambda} = \frac{V}{4L}

The wavelength of the sound for the first harmonic is calculated;

L = Node ----> Node + Node ------> Antinode

L = \frac{\lambda}{2} + \frac{\lambda}{4} = \frac{2\lambda+\lambda}{4} = \frac{3\lambda}{4} \\\\\lambda = \frac{4 L}{3}

Second harmonic: F_1 =  \frac{V}{\lambda} = \frac{3V}{4L}

F₁ = 3F₀

The increment from F₀ to F₁ is 1 to 3; (odd number).

(1, 3, 5, 7, 9, 11, 13, 15, 17, 19..... n+2, where n is odd number)

The 9th harmonic = F₈

F₈ = 15F₀

F_8= 17(F_0) = 15 (\frac{V}{4L} )\\\\F_8 = 15(\frac{331.5}{4\times 1.23} )\\\\F_8 = 1,010.67 \ Hz

Therefore, the 9th harmonic is 1,010.67 Hz.

8 0
3 years ago
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