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notsponge [240]
3 years ago
11

Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 2.4

m. a person is standing 10.0 m away from the wall, equidistant from the loudspeakers. when the person moves 0.20 m parallel to the wall, she experiences destructive interference for the first time. what is the frequency of the sound? take the speed of sound in air to be 343 m/s.
Physics
1 answer:
NeX [460]3 years ago
5 0

When person is observing destructive interference at 0.20 m distance from the equidistant position then we can say that path difference must be equal to half of the wavelength

now we will have

\frac{\lambda}{2} = \frac{yd}{L}

now we know that

y = 0.20 m

d = 2.4 m

L = 10 m

now here we have

\frac{\lambda}{2} = \frac{0.20\times 2.4}{10}

\lambda = 0.096 m

now frequency of wave is given as

f = \frac{v}{\lambda}

f = \frac{343}{0.096} = 3573 Hz

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3 0
3 years ago
A ball is thrown at an angle of to the ground. If the ball lands 90 m away, what was the initial speed of the ball?
andre [41]

Answer:

The initial speed of the ball is 30 m/s.

Explanation:

It can be assumed that the ball is thrown at an angle of 45 degrees to the ground. The ball lands 90 m away. We need to find the initial speed of the ball. We know that the horizontal distance covered by the projectile is called its range. It is given by :

R=\dfrac{u^2\ sin2\theta}{g}

u is the initial speed of the ball.

v=\sqrt{\dfrac{Rg}{sin2\theta}}

v=\sqrt{\dfrac{90\times 9.8}{sin2(45)}}

v = 29.69 m/s

or

v = 30 m/s

So, the initial speed of the ball is 30 m/s. Hence, this is the required solution.                                      

8 0
3 years ago
Jason and Guy are throwing watermelons straight up from the ground. (They’re making fruit salad.) Jason throws his watermelon at
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Answer:2t

Explanation:

Given

Jason throwing watermelon at speed v and it spend t time in air

time to reach max height

v_f=u_i+at'

0=v-gt'

t'=\frac{v}{g}

and time to reach bottom is also t'

t=2t'

t=2\frac{v}{g}

For guy throws his watermelon at speed 2v

So total time in air will be

t''=2\frac{2v}{g}

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What is the greatest velocity which a falling object can achieve while falling through the air?
Alik [6]

Answer:

Terminal Velocity

Explanation:

6 0
3 years ago
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