The rocket engine works on the basic principle proposed by Newton which is Newton’s Third Law.
<u>Answer:</u>
The acceleration of the car is ![3.13 m/s^2](https://tex.z-dn.net/?f=3.13%20m%2Fs%5E2)
<u>Explanation:</u>
In the question it is given that car initially heads north with a velocity
. It then accelerates for
and in the end its velocity is
.
initial velocity ![u = 15 m/s](https://tex.z-dn.net/?f=u%20%3D%2015%20m%2Fs)
time ![t=4.25 s](https://tex.z-dn.net/?f=t%3D4.25%20s)
final velocity ![v=28.3 m/s](https://tex.z-dn.net/?f=v%3D28.3%20m%2Fs)
The equation of acceleration is
![a= \frac{(v-u)}{t}](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7B%28v-u%29%7D%7Bt%7D)
![= \frac{(28.3-15)}{4.25} = \frac {13.3}{4.25} =3.13m/s^2](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B%2828.3-15%29%7D%7B4.25%7D%20%3D%20%20%5Cfrac%20%7B13.3%7D%7B4.25%7D%20%3D3.13m%2Fs%5E2)
The value of acceleration is positive, here since the car is speeding up. If it was slowing down the value of acceleration would be negative.
I can't find the attached circuit.
Maximum power transfer occurs when the load impedance
is equal to the internal impedance of the power source.
Answer:
<h3><u>If the mass of both of the objects is doubled, then the force of gravity between them is quadrupled; and so on. Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.</u></h3>