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Pani-rosa [81]
2 years ago
10

Select the lewis structure for xeo2f2 which correctly minimizes formal charges.

Chemistry
1 answer:
sweet-ann [11.9K]2 years ago
6 0

Answer:

explanation and image attached

Explanation:

Our aim is to draw a structure of XeO2F2 whith the least formal charges. We must remember that the compound has 34 valence electrons.

To obtain the least formal charges then Xe must have a total of twelve electrons on its valence shell instead of eight.

The other atoms around the central Xe atom are arranged as shown in the image attached.

Image Credit: UCLA

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Oxygen is an example of a(n)
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Answer:

C. element. oxygen is an element

Explanation:

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3 years ago
125 ml of nitrogen gas is collected at 70.0 degrees Celsius. The pressure
dybincka [34]

Answer: Volume of the gas at STP is 22.53 L.

Explanation:

Given : Volume = 125 mL   (as 1 mL = 0.001 L) = 0.125 L

Temperature = 70^{o}C = (70 + 273) K = 343 K

Pressure = 125 kPa = 125 kPa \times \frac{0.01 atm}{1 kPa} = 1.25 atm

According to the ideal gas equation, the volume of given nitrogen gas is calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

1.25 atm \times V = 1 mol \times 0.0821 L atm/mol K \times 343 K\\V = \frac{1 mol \times 0.0821 L atm/mol K \times 343 K}{1.25 atm}\\= \frac{28.1603}{1.25} L\\= 22.53 L

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5 0
3 years ago
My teacher is grading this soon can someone help me ASAP!
Stolb23 [73]

10. You demonstrated the difference in density of the two objects. It is a physical property.

11. First calculate the density for all of them: density = mass/volume

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A. 5/6 g/ml

B. 10/9 g/ml

C. 15/16 g/ml

D. 20/10 g/ml

If the density of the substance is higher than the density of the substance it is put in, then it will sink. So substances B and D will sink in water, as their densities are higher than 1 g/ml.

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3 0
3 years ago
44. Convert the following. Express your answers in
professor190 [17]

Answer:

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7.5 ×10⁴ / 1000 = 0.75 ×10² KJ.

Joule is the smaller unit while kilo joule is the larger unit. One kilo joule equals to the thousand joule that's why we will divide the given value by 1000 in order to convert into KJ.

B = 3.9 ×10⁵ mg to decigrams.

3.9 ×10⁵ / 100 = 3.9 ×10³ dg

Decigram is larger unit while milligram is smaller unit. One decigram is equal to the 100 milligram. In order to convert the given value into  decigram we have to divide the value by 100.

C = 2.21 ×10⁻⁴ dL to micorliters

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4 0
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steposvetlana [31]
The answer is 99.10.
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