Select the lewis structure for xeo2f2 which correctly minimizes formal charges.

Chemistry

1 answer:

sweet-ann [11.9K]2 years ago

6 0

Answer:

explanation and image attached

Explanation:

Our aim is to draw a structure of XeO2F2 whith the least formal charges. We must remember that the compound has 34 valence electrons.

To obtain the least formal charges then Xe must have a total of twelve electrons on its valence shell instead of eight.

The other atoms around the central Xe atom are arranged as shown in the image attached.

Image Credit: UCLA

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