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notka56 [123]
2 years ago
15

There are two isotopes of an unknown element, X-19 and X-21. The abundance of X-19 is 14.55%. A weighted average uses the percen

tages of each isotope to scale their contribution to the total mass. Each isotope's contribution is the percentage (in decimal form) multiplied by the mass of the isotope. What is the contribution (in amu) to the weighted average from the X-19 isotope, which has a mass of 19.00 amu
Chemistry
1 answer:
alekssr [168]2 years ago
8 0

Answer:

2.765amu is the contribution of the X-19 isotope to the weighted average

Explanation:

The average molar mass is defined as the sum of the molar mass of each isotope times its abundance. For the unknown element X that has 2 isotopes the weighted average is defined as:

X = Mass X-19 * Abundance X-19 + MassX-21 * Abundance X-21

The contribution of the X-19 isotope is its mass (19.00 amu) times its abundance (14.55% = 0.1455). That is:

19.00amu * 0.1455 =

2.765amu is the contribution of the X-19 isotope to the weighted average

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Answer:

Ni^2+

Explanation:

The following data were obtained from the question:

Proton = 28

Electron = 26

Neutron = 34

Next, we shall determine the atomic number of the element.

Atomic number of an element is simply defined as the number of protons in the atom of an element.

Thus,

Atomic number = proton number

Proton = 28

Atomic number = proton number = 28

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Therefore, the element is Nickel since no two elements have the same atomic number.

Finally, we shall determine the charge on the Nickel atom as follow:

Proton = 28

Electron = 26

Charge on atom =

Charge on atom = Proton – Electron

Charge on atom = 28 – 26

Charge on atom = +2

Therefore, we can represent the Particle as Ni^2+

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