3 years ago

Question 14 (8 points)

Chemistry

1 answer:

maxonik [38]3 years ago

8 0

Answer:

Explanation:

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A monoprotic weak acid, HA , dissociates in water according to the reaction HA(aq)↽−−⇀H+(aq)+A−(aq) The equilibrium concentratio

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Answer:

$pK_{a}$ of HA is 6.80

Explanation:

$pK_{a}=-logK_{a}$

Acid dissociation constant ( $K_{a}$ ) of HA is represented as-

$K_{a}=\frac{[H^{+}][A^{-}]}{[HA]}$

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$K_{a}=\frac{(2.00\times 10^{-4})\times (2.00\times 10^{-4})}{0.250}$

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Hence $pK_{a}=-log(1.6\times 10^{-7})=6.80$

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3 years ago