The equation is:
Ca(OH)₂(s) + 2 HCl(aq) → CaCl₂(aq) + 2 H₂<span>O(l)
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n=mass in g/M.M
15 g Ca(OH)₂ is n=15 g/ 74.1 g/mol=0.2024 mol of Ca(OH)₂
no. of mol of HCl:
n=0.5 mol/L*0.075L=0.0375 mol
This could react with 0.0375/2= 0.01875 mol of Ca(OH)₂ We have a lot more than that.
Therefore, HCl is the limiting reagent and determines how much CaCl₂ forms.
Based on the balanced reaction, 2 moles of HCl gives 1 mole of CaCl₂
no. of mol of CaCl₂= 0.0375/2= 0.01875 mol
mass in g=n*MM= 0.01875*111= 2.08 g
For this reaction, the reactants are nitrogen dioxide, oxygen and water while the product would be nitric acid. The chemical equation would be written as:
NO2(g) + O2(g) + H2O(l) --> HNO3(aq)
This can be a complete equation when the elements are balanced in each side.
4NO2(g) + O2(g) + 2<span>H2O(l) --> 4HNO3(aq)</span>
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