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3 years ago

How many significant figures are in 8.00 (10)-3

Chemistry

1 answer:

Kay [80]3 years ago

6 0

Answer: 1 significant figure

Explanation: 8.00*10^-3 is simply 1000/8 which will give you 0.008 and in significant numbers do not count zero.

So there you have one significant figure which is the figure 8

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How many Liters of a 4.5 M HCL solution can be prepared by using 250.0 mL of a 12.0 M HCl solution?

netineya [11]

Answer:

0.667 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 250 mL

Initial concentration (C₁) = 12 M

Final concentration (C₂) = 4.5 M

Final volume (V₂) =?

The final volume of the solution can be obtained by using the dilution formula as illustrated below:

C₁V₁ = C₂V₂

12 × 250 = 4.5 × V₂

3000 = 4.5 × V₂

Divide both side by 4.5

V₂ = 3000 / 4.5

V₂ = 667 mL

Finally, we shall convert 667 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

667 mL = 667 mL × 1 L / 1000 mL

667 mL = 0.667 L

Thus, the volume of the solution prepared is 0.667 L

3 0

3 years ago

A fact of nature that has been confirmed many times by observation is known as a(n).

BlackZzzverrR [31]

Answer:

law(scientific law)

Explanation:

8 0

4 years ago

The rate constant for a certain reaction is k = 5.40×10−3 s−1 . If the initial reactant concentration was 0.100 M, what will the

IceJOKER [234]

Answer : The concentration after 17.0 minutes will be, $4.05\times 10^{-4}M$

Explanation :

The expression for first order reaction is:

$[C_t]=[C_o]e^{-kt}$

where,

$[C_t]$ = concentration at time 't' (final) = ?

$[C_o]$ = concentration at time '0' (initial) = 0.100 M

k = rate constant = $5.40\times 10^{-3}s^{-1}$

t = time = 17.0 min = 1020 s (1 min = 60 s)

Now put all the given values in the above expression, we get:

$[C_t]=(0.100)\times e^{-(5.40\times 10^{-3})\times (1020)}$

$[C_t]=4.05\times 10^{-4}M$

Thus, the concentration after 17.0 minutes will be, $4.05\times 10^{-4}M$

4 0

3 years ago

What property do all of the group 18 elements have that make them stand out from other elements?

matrenka [14]

They are very stable (not reactive).

This is because their outer shell has a total of 8 valence electrons. All elements strive to get towards a full outer shell, but since these elements already have a full outer shell, they are fairly unreactive.

5 0

3 years ago

PLEASE HELP!! WILL REWARD BRAINLIEST!!!

Irina-Kira [14]

Oxidation number of sulphur in S is 0, in SCl2 is +2, in SO3 is +6, in H2S is - 2, in S2Cl2 is +1, in H2SO4 is +6.

<h3><u>Explanation</u>:</h3>

Oxidation number is the numeric representation of the charge of the particular atom in a compound assuming the compound is 100% ionic in character. This oxidation number is calculated based on the electronegativity of the participating atoms and the valemct of the atoms.

In S, there are no other atoms except sulphur. So its an elemental atom and elemental atoms have oxidation number of 0.

In SCl2, chlorine is more electronegative than sulphur, so chlorine is given - 1 based on its valency and electronegativity. So sulphur will have the oxidation number of +2.

In SO3, oxygen is more electronegative than sulphur, so given - 2 based on its valency and electronegativity. So sulphur will be +6.

In H2S, hydrogen is electropositive than sulphur, so given +1. So the oxidation number of sulphur will be - 2.

In S2Cl2, chlorine is more electronegative than sulphur, so chlorine is given - 1 based on its valency and electronegativity. So sulphur will have the oxidation number of +1.

In H2SO4, hydrogen is electropositive than sulphur, so given +1 and oxygen is more electronegative than sulphur, so given - 2. So oxidation number of sulphur will be +6.

6 0

4 years ago