Question

John bought an odd shaped lot that was 100 feet deep, but the front footage was 160 feet and the length of the back side of the lot was 80 feet what is the square footage of his lot?

Answer 1

This lot has the shape of a trapezoid. Regard the 2 different lengths as 160' and 80' and the width 100'

Applying the formula for the area of a trapezoid:

80' + 160'

A = ----------------- * 100' = 24000 ft^3

2

Answer 2

Answer:

12000 $ft^{2}$

Step-by-step explanation:

The lot has the shape of a trapezoid.  This means that the area can be find using the formula:

$Area= (\dfrac{B_{1}+B_{2}}{2})h$

Where $B_{1}$ and $B_{2}$ are the two paralle sides (in this case the front side of 160 feet and, the back side of 80) and, h is the height (the deep of 100 feet). So :

$Area= (\dfrac{160+80}{2})*100$

$Area= 12000$ square feet.