Answer:
The components of the moving frame is (8.07c, -2, 3, 9.493)
Solution:
As per the question:
Velocity of moving frame w.r.t original frame 0.85c
Point 'a' of an event in one reference frame corresponds to the (x, y, z, t) coordinates of the plane
a = (0, - 2, 3, 5)
Now, according the the question, the coordinates of moving frame, say (X, Y, Z, t'):
New coordinates are given by:
X =
X =
X =
Now,
Y = y = - 2
Z = z = 3
Now,
Answer:
For left = 0 N/C
For right = 0 N/C
At middle = N/C
Explanation:
Given data :-
б = C/ m²
Considering the two thin metal plates to be non conducting sheets of charges.
Electric field is given by
1) To the left of the plate
= 0 N/C.
2) To the right of them.
= 0 N/C.
3) Between them.
=
=
=
N/C
a) 120 s
b) v = 0.052R [m/s]
Explanation:
a)
The period of a revolution in a simple harmonic motion is the time taken for the object in motion to complete one cycle (in this case, the time taken to complete one revolution).
The graph of the problem is missing, find it in attachment.
To find the period of revolution of the book, we have to find the time between two consecutive points of the graph that have exactly the same shape, which correspond to two points in which the book is located at the same position.
The first point we take is t = 0, when the position of the book is x = 0.
Then, the next point with same shape is at t = 120 s, where the book returns at x = 0 m.
Therefore, the period is
T = 120 s - 0 s = 120 s
b)
The tangential speed of the book is given by the ratio between the distance covered during one revolution, which is the perimeter of the wheel, and the time taken, which is the period.
The perimeter of the wheel is:
where R is the radius of the wheel.
The period of revolution is:
Therefore, the tangential speed of the book is:
