Answer:
Explanation:
v = u +at
u = 0
a = 2.3 m /s²
t = 20 s
v = 2.3 x 20
= 46 m /s
Distance covered under acceleration of 2.3 m/s²
s = ut + 1/2 at²
= 0 + .5 x 2.3 x 20²
= 460 m
After that it moves under free fall ie g acts on it downwards .
v² = u² - 2gh , h is height moved by it under free fall
0 = 46² - 2 x 9.8 h
h = 107.96 m
Total height attained
= 460 + 107.96
= 567.96 m
b ) At its highest point ,it stops so its velocity = 0
c ) rocket's acceleration at its highest point = g = 9.8 downwards .
At highest point , it is undergoing free fall so its acceleration = g
Answer:
Explanation:
Mass of the sum =
70% of this mass is
Mass of hydrogen in the sun is
Mass of a hydrogen atom =
Dividing the mass hydrogen in the sun by the mass of one hydrogen atom will give us the number of hydrogen atoms
The number hydrogen atoms in the Sun is
Answer:
15
Explanation:
displacement = initial position - final position
Answer: Planning
Explanation: cause i got it right
Answer:
h₂ = 27.22m : height the pellet reaches
Explanation:
Pellet kinetics
Pellet moves with uniformly accelerated movement in
freefall
v f₁²=v₀²+2g*h₁ (formula 1) : ball movement down
v f₂²=v₀²-2g*h₂ (formula (formula 2) : ball movement up
d:displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
g: acceleration due to gravity in m/s²
h :height in m
Known data
g=9.8 m/s²
h₁=12.7m
v f₁= 27.9 m/s
Initial velocity calculation (v₀)
We replace the data in formula 1:
27.9²=v₀²+2*9.8* 12.7
27.9²-2*9.8* 12.7=v₀²
529.49=v₀²
Calculation of the height that the pellet reaches when it goes up
Data:
v f₂=0 :When the pellet reaches the maximum height the final speed is zero
We replace the data in formula (2)
0²=23.1²-2*9.8*h₂
19.6h₂ =23.1²
h₂ =23.1²÷19.6
h₂ =27.22m