Imagine we have <span>mass of solvent 1kg (1000g)
According to that: </span>
= 4.8 mole * 98 g/mole = 470g
m(H2SO4) which is =<span>470g
</span><span>m(solution) = m(H2SO4) + m(solvent) = 470 + 1000 = 1470 g
d(solution) = m(solution) / V(solution) =>
=> 1.249 g/mL = 1470 g / V(solution) =></span>
(16.3 L) / (22.414 L/mol) x (4.0026 g He/mol) = 2.91 g
Answer:
The answer is B. Limiting factors can lower birth rates, increase death rates.
From the given balanced equation we have find out the amount (in gm) of Ag formed from 5.50 gm of Ag₂O.
2Ag₂O(s) → 4Ag (s) + O₂ (g)
We know, molecular mass of Ag₂O= 231.7 g/mol, and atomic mass of Ag= 107.8 g/mol. Given, mass of Ag₂O=5.50 gm. Number moles of Ag₂O=
= 0.0237 moles.
From the balanced chemical reaction we get 2 (two) moles of Ag₂O produces 4 (four) moles of Ag. So, 0.0237 moles of Ag₂O produces 
moles=0.0474 moles of Ag= 0.0474 X 107.8 g of Ag=5.11g Ag.
Therefore, 5.50 g Ag₂O produces 5.11 g of Ag as per the given balanced chemical reaction.
Hi Jojo
The 4 factors that makes a good fuel are
1) It should be cheap
2)It should not burn too fast or too slowly
3) It should be easily available
4) It should have a high calorific value
I hope that's help !
