Answer:
B) The chromosomes in the cell lack a homologous pair in the same cell
Explanation:
Meiosis is the cellular division that reduces the chromosomal number of the parent cell by half in the daughter cells produced. In a somatic (body) human cell, chromosomes are found in homologous pairs i.e. each pair coming from each parent to form a diploid organism (2n).
However, when meiosis occurs, this homologous pair is separated into individual chromosomes. This is the case of the human cell which contains 46 chromosomes or 23 pairs of chromosomes. Each pair is an homolog of the other, however, meiotic division causes the homologs to separate. This will cause the chromosomes in the cell lack a homologous pair in the same cell.
When m for water is only 5 % so, m for the acid is (m%) = 95%
and D = 1.84 g/ml, assume 1 L of solution therefore,
1- D= m / v
m = D x v = 1.84 g/ml x 1 L x 10^3 ml /L
= 1840 g solution
2- m% = m acid / m sol x 100 %
m acid = 1840 g H2So4 x 0.95
= 1750 g H2So4
3- n = 1750 g H2So4 x 1 mol H2So4 x 98.09 H2So4
= 17.8 mol H2So4
4- So the molarity of { H2So4} = n / v = 17.8 mol H2So4 / 1 L
= 17.8 M
Answer:
1st step : mix the mixture with water that way A will dissolve while B will remain insoluble.
2nd step :To get B from the solution, filter the mixture and get B
3rd step : To get A from the solution evaporate the new solution
Explanation:
Assuming 2mg of impurity B to be present
100 mg of A is present as well
<u>Method of purifying A given that B is of same solubility </u>
Dissolve the 100 mg of A with 30 mL
1st step : mix the mixture with water that way A will dissolve while B will remain insoluble.
2nd step :To get B from the solution, filter the mixture and get B
3rd step : To get A from the solution evaporate the new solution
The balanced equation is 2H2+O2=2H2O i think
The best way to prevent the corrosion of iron is to paint the exposed iron with protective paint, because that prevents water from rusting the iron.
