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8_murik_8 [283]
3 years ago
13

The density of a 22.0% by mass ethylene glycol (c2h6o2) solution in water is 1.04 g/ml . part a find the molarity of the solutio

n.
Chemistry
1 answer:
julsineya [31]3 years ago
4 0

Answer:- 3.68M.

Solution:- We have a 22.0% by mass solution of ethylene glycol and it's density is 1.04 gram per mL. It ask to calculate the molarity of the solution. We know that molarity is moles of solute per liter of solution. So, we need to figure out the moles of ethylene glycol and volume of solution.

Let's say we have 100 grams of the solution. Then mass of ethylene glycol would be 22.0 grams. Molar mass of ethylene glycol is 62.07 gram per mol.

Let's calculate it's moles first:

22.0gC_2H_6O_2(\frac{1mol}{62.07g})

= 0.354molC_2H_6O_2

From mass and density we calculate the volume of the solution and convert it to liters as:

100g(\frac{1mL}{1.04g})(\frac{1L}{1000mL})

= 0.0962 L

molarity=\frac{0.354mol}{0.0962L}

= 3.68M

So, the molarity of ethylene glycol solution is 3.68M.

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We can solve this by the method of which i solved your one question earlier

so again here molar mass of C12H25NaSO4 is 288.372 and number of moles for 11900 gm of C12H25NaSO4 will be = 11900/288.372

which is almost = 41.26 moles

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