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Anton [14]
3 years ago
13

Hydrogen is special because it can act like two groups, _____ and _____

Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
4 0

Answer: gas and alkaline earth metal

Explanation:

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Which term names the container that holds the gear box and generator in a wind power system?.
spayn [35]

Answer:

Nacelle. The nacelle sits atop the tower and contains the gearbox, low- and high-speed shafts, generator, and brake.

Explanation:

5 0
2 years ago
Iron (Fe) is classified as a metal while Silicon (Si) is classified as a metalloid. Which physical property do these two element
sp2606 [1]
I’ll try to get someone to help you I got you bro I’m gonna go find somebody got you
4 0
3 years ago
Which of the following devices can measure only atmospheric pressure?        A. Pressure gauge   B. Barometer   C. Tire gauge  
Kamila [148]
B.) Barometer

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8 0
3 years ago
Urea, (NH2)2CO, is a product of metabolism of proteins. An aqueous solution is 37.2% urea by mass and has a density of 1.032 g/m
Feliz [49]

Answer:

The molarity of urea in this solution is 6.39 M.

Explanation:

Molarity (M) is <em>the number of moles of solute in 1 L of solution</em>;  that is

molarity = moles of solute ÷ liters of solution

To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.

Our first step is to calculate the moles of urea in 100 grams of the solution,

using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is

60.06 g/mol ÷ 37.2 g = 0.619 mol

Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.

1.032 g/mL ÷ 100 g = 96.9 mL

This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.

0.619 mol/96.9 mL × 1000 mL= 6.39 M

Therefore, the molarity of the solution is 6.39 M.

4 0
3 years ago
The combustion of ethane ( C 2 H 6 ) (C2H6) produces carbon dioxide and steam. 2 C 2 H 6 ( g ) + 7 O 2 ( g ) ⟶ 4 CO 2 ( g ) + 6
REY [17]

Answer:

There is a production of 11.6 moles of CO₂

Explanation:

The reaction is this:

2C₂H₆(g)  +  7O₂(g)  ⟶  4CO₂(g)  +  6H₂O(g)

2 moles of ethane reacts with 7 moles of oxygen, to make 4 mol of dioxide and 6 moles of water vapor.

If the oxygen is in excess, we make the calculate with the ethane (limiting reactant)

2 moles of ethane produce 4 moles of dioxide

5.8 moles of ethane produce (5.8  .4)/2 = 11.6 moles

5 0
3 years ago
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