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saveliy_v [14]
3 years ago
7

A blacksmith hammers a hot piece of iron while making a tool.How does the force due to hammering effect the piece of iron ???

Physics
1 answer:
Whitepunk [10]3 years ago
4 0

Answer:

The force due to hammering changes the shape of the piece of iron

Explanation:

How hard you hammer the iron while it is hot will cause the iron to change shape or reform the way you want it.

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A balloon-powered car rolls across the floor at a speed of 0.711 m/s. How long does it take to cover 8.25 m?
devlian [24]

Answer:

Time = 11.60 seconds.

Explanation:

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the equation;

Speed = \frac{distance}{time}

Given the following data;

Speed = 0.711m/s

Distance = 8.25m

To find the time;

Making time the subject of formula, we have;

Time = \frac{distance}{speed}

Substituting into the equation, we have;

Time = \frac{8.25}{0.711}

Time = 11.60 secs.

5 0
2 years ago
True or False? PLEASE HELP ME​
viva [34]

Answer:

a. True - Joules is the unit measure for energy.

b. False - Potential energy is associated with position

c. False - Kinetic energy is associated with movement.

d. False - It's climbing, which means it also has kinetic energy.

6 0
3 years ago
Un joven pelotero llamado Saúl en su primer año de ser firmado en grandes ligas, batea varias veces de cuadrangular, el segundo
Brilliant_brown [7]

Answer:

135-15=120

120÷3=40

40+40+(10)+40+(5)=135

8 0
2 years ago
Read 2 more answers
The older, geocentric model of the solar system placed the__________ at the center. Today's heliocentric model places the_______
DedPeter [7]

the answer is earth for the first one and sun for the second one

3 0
3 years ago
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A transformer connected to a 120-v(rms) at line is to supply 13,000V(rms) for a neon sign.
lyudmila [28]

Answer:

(a) 108

(b) 110.500 kW

(c) 920.84 A

Solution:

As per the question:

Voltage at primary, V_{p} = 120\ V          (rms voltage)

Voltage at secondary, V_{s} = 13000\ V  (rms voltage)

Current in the secondary, I_{s} = 8.50\ mA  

Now,

(a) The ratio of secondary to primary turns is given by the relation:

\frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{s}}

where

N_{p} = No. of turns in primary

N_{s} = No. of turns in secondary

\frac{N_{s}}{N_{p}} = \frac{13000}{120} ≈ 108

(b) The power supplied to the line is given by:

Power, P = V_{s}I_{s} = 13000\times 8.50 = 110.500\ kW

(c) The current rating that the fuse should have is given by:

\frac{V_{s}}{V_{p}} = \frac{I_{p}}{I_{s}}

\frac{13000}{120} = \frac{I_{p}}{8.50}

I_{p} = \frac{13000}{120}\times 8.50 = 920.84\ A

 

6 0
3 years ago
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