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3 years ago

A blacksmith hammers a hot piece of iron while making a tool.How does the force due to hammering effect the piece of iron ???

Physics

1 answer:

Whitepunk [10]3 years ago

4 0

Answer:

The force due to hammering changes the shape of the piece of iron

Explanation:

How hard you hammer the iron while it is hot will cause the iron to change shape or reform the way you want it.

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A balloon-powered car rolls across the floor at a speed of 0.711 m/s. How long does it take to cover 8.25 m?

devlian [24]

Answer:

Time = 11.60 seconds.

Explanation:

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the equation;

$Speed = \frac{distance}{time}$

Given the following data;

Speed = 0.711m/s

Distance = 8.25m

To find the time;

Making time the subject of formula, we have;

$Time = \frac{distance}{speed}$

Substituting into the equation, we have;

$Time = \frac{8.25}{0.711}$

Time = 11.60 secs.

5 0

2 years ago

True or False? PLEASE HELP ME

viva [34]

Answer:

a. True - Joules is the unit measure for energy.

b. False - Potential energy is associated with position

c. False - Kinetic energy is associated with movement.

d. False - It's climbing, which means it also has kinetic energy.

6 0

3 years ago

Un joven pelotero llamado Saúl en su primer año de ser firmado en grandes ligas, batea varias veces de cuadrangular, el segundo

Brilliant_brown [7]

Answer:

135-15=120

120÷3=40

40+40+(10)+40+(5)=135

8 0

2 years ago

Read 2 more answers

The older, geocentric model of the solar system placed the__________ at the center. Today's heliocentric model places the_______

DedPeter [7]

the answer is earth for the first one and sun for the second one

3 0

3 years ago

Read 2 more answers

A transformer connected to a 120-v(rms) at line is to supply 13,000V(rms) for a neon sign.

lyudmila [28]

Answer:

(a) 108

(b) 110.500 kW

Solution:

As per the question:

Voltage at primary, $V_{p} = 120\ V$ (rms voltage)

Voltage at secondary, $V_{s} = 13000\ V$ (rms voltage)

Current in the secondary, $I_{s} = 8.50\ mA$

Now,

(a) The ratio of secondary to primary turns is given by the relation:

$\frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{s}}$

where

$N_{p}$ = No. of turns in primary

$N_{s}$ = No. of turns in secondary

$\frac{N_{s}}{N_{p}} = \frac{13000}{120}$ ≈ 108

(b) The power supplied to the line is given by:

Power, P = $V_{s}I_{s} = 13000\times 8.50 = 110.500\ kW$

$\frac{V_{s}}{V_{p}} = \frac{I_{p}}{I_{s}}$

$\frac{13000}{120} = \frac{I_{p}}{8.50}$

$I_{p} = \frac{13000}{120}\times 8.50 = 920.84\ A$

6 0

3 years ago