Answer:
T = 5163.89 N
Explanation:
Newton's first law:
∑F =0 Formula (1)
∑F : algebraic sum of the forces in Newton (N)
We define the x-axis in the direction parallel to the movement of the car on the ramp and the y-axis in the direction perpendicular to it.
Forces acting on the car
W: Weight of the car : In vertical direction
FN : Normal force : perpendicular to the ramp
T :Tension force: at angle of 31.0° above the surface of the ramp
Calculated of the Weight of the car (W)
W = m*g m: mass g:acceleration due to gravity
W = 1130-kg* 9.8 m/s² = 11074 N
x-y weight components
Wx = 11074 N*sin 25.0° = 4680.07 N
Wy = 11074 N*cos 25.0° = 10036.45 N
x-y Tension components
Tx = T*cos 25.0°
Ty = T*sin 25.0°
Newton's first law:
∑Fx =0 Formula (1)
Tx-Wx = 0
T*cos 25.0° - 4680.07 = 0
T*cos 25.0° = 4680.07
T = 4680.07 / cos 25.0°
T = 5163.89 N
Answer:
Walking’ - If a handball player takes more than three steps without dribbling (bouncing the ball) or holds the ball for more than 3 seconds without bouncing it, shooting or passing, then that is deemed ‘walking' and possession is lost.
'Double dribble’ - Handball players cannot receive the ball and bounce it, then hold the ball, and bounce it again. This is termed ‘double dribble’ and is against the rules.
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Answer:
Explanation:
let 
be the mass attached, let 
be the spring constant and let 
be the positive damping constant.
-By Newton's second law:
where 
is the displacement from equilibrium position. The equation can be transformed into:
shich is the equation of motion.
Answer:
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Explanation:
Initial speed u=80 km/h=80×185=22.22 m/s
Final speed v=60 km/h=60×185=16.67 m/s
Using v=u+at
Or 16.67=22.22+α×5
⟹ a=−1.1 m/s2
