Question

You are moving the robot to your classroom, which measures 30 feet by 40 feet.

Answer 1

Answer:

1) See figure attached

2)

a) $d = \sqrt{(x_2 -x_1)^2 +(y_2 -y_1)^2}$

And if we replace we got:

$d = \sqrt{(10 -6)^2 +(15 -9)^2}= 7.211$

b) $V = \frac{d}{t}$

And if we replace we got:

$V = \frac{7.211 ft}{2 sec}=3.606 s$

Step-by-step explanation:

Part 1

We can see the plot in the figure attached.

Part 2

a)

For this case we have two points $(x_1 , y_1) = (6,9) , (x_2 , y_2) = (10,15)$

And we want to find the distance travelled between these two points and we can use the following formula from the euclidian distance between two points:

$d = \sqrt{(x_2 -x_1)^2 +(y_2 -y_1)^2}$

And if we replace we got:

$d = \sqrt{(10 -6)^2 +(15 -9)^2}= 7.211$

b)

Since it takes two seconds in order to go from (6.9) to (10,15) we can use the definition of velocity:

$V = \frac{d}{t}$

And if we replace we got:

$V = \frac{7.211 ft}{2 sec}=3.606 s$