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3 years ago

What makes speed, velocity, acceleration, distance, and time different?

Physics

1 answer:

LekaFEV [45]3 years ago

8 0

Explanation:

Speed is the rate of change of distance with time.

Speed = $\frac{distance}{time}$

Velocity is given as the displacement per unit of time:

Velocity = $\frac{displacement}{time}$

Speed and velocity are similar but speed is a scalar quantity while velocity is a vector quantity. Speed has magnitude but does not point towards a specific direction. Velocity shows both magnitude and direction and it is a vector quantity.

Acceleration is given as the change in velocity with time. It is a vector quantity:

Acceleration = $\frac{change in velocity}{time}$

Distance is how far a body moves. It is scalar quantity.
Time is the duration of an event. It is a scalar quantity.

Learn more:

Vector calculation brainly.com/question/2678571

#learnwithBrainly

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Answer:

$v=10.777m/s$

Explanation:

Tarzan swing can be thought of as change in potential energy by going from higher location We solve for height of beginning of the swing by using simple cosine equation:

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$=m*9.81(31-25.08)\\$

The potential energy of Tarzan initial position is converted into kinetic energy of his swing.By using kinetic equation

$E_{kinectic}=P_{potential}\\1/2mv^{2}=m*9.81(31.0-25.08)\\(1/2)v^{2}=9.81(31.0-25.08)\\0.5v^{2}=58.07\\v^{2}=58.07/0.5\\v=\sqrt{58.07/0.5}\\ v=10.777m/s$

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3 years ago

A 15.0-gram lead ball at 25.0°C was heated with 40.5 joules of heat. Given the specific heat of lead is 0.128 J/g∙°C, what is th

mr Goodwill [35]

Answer:

$T=4985.5^{\circ}K$

Explanation:

The equation that relates heat Q with the temperature change $T-T_0$ of a substance of mass <em>m </em>and specific heat <em>c </em>is $Q=mc(T-T_0)$ .

We want to calculate the final temperature <em>T, </em>so we have:

$T=\frac{Q}{mc}+T_0$

Which for our values means (in this case we do not need to convert the mass to Kg since <em>c</em> is given in g also and they cancel out, but we add $273^{\circ}$ to our temperature in $^{\circ}C$ to have it in $^{\circ}K$ as it must be):

$T=\frac{Q}{mc}+T_0=\frac{40.5J}{(15g)(0.128J/g^{\circ}C)}+(298^{\circ}K)=4985.5^{\circ}K$

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3 years ago

Which describes radioactive decay of a substance?

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4 years ago

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Explanation:

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Answer:

$Q_{in} = 25349.92\,kJ$

Explanation:

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The heat transfered to the cooker is:

$Q_{in} = m_{2}\cdot h_{2} - m_{1}\cdot h_{1} + (m_{1}-m_{2})\cdot u_{2}-m_{1}\cdot u_{1}$

Properties at each state are described below:

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$h_{1} = 83.915\,\frac{kJ}{kg}$

State 2

$u_{2} = 2540.1\,\frac{kJ}{kg}$

$h_{2} = 2720.9\,\frac{kJ}{kg}$

The heat transfered to the cooker is:

$Q_{in} = (9\,kg)\cdot (2720.9\,\frac{kJ}{kg} ) - (10\,kg)\cdot (83.915\,\frac{kJ}{kg} ) + (1\,kg) \cdot (2540.1\,\frac{kJ}{kg} )-(10\,kg)\cdot (83.913\,\frac{kJ}{kg} )$

$Q_{in} = 25349.92\,kJ$

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3 years ago

What makes speed, velocity, acceleration, distance, and time different?​

What makes speed, velocity, acceleration, distance, and time different?