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3 years ago

What makes speed, velocity, acceleration, distance, and time different?

Physics

1 answer:

LekaFEV [45]3 years ago

8 0

Explanation:

Speed is the rate of change of distance with time.

Speed = $\frac{distance}{time}$

Velocity is given as the displacement per unit of time:

Velocity = $\frac{displacement}{time}$

Speed and velocity are similar but speed is a scalar quantity while velocity is a vector quantity. Speed has magnitude but does not point towards a specific direction. Velocity shows both magnitude and direction and it is a vector quantity.

Acceleration is given as the change in velocity with time. It is a vector quantity:

Acceleration = $\frac{change in velocity}{time}$

Distance is how far a body moves. It is scalar quantity.
Time is the duration of an event. It is a scalar quantity.

Learn more:

Vector calculation brainly.com/question/2678571

#learnwithBrainly

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4 years ago

A long cylindrical capacitor is made of a central wire of radius a = 2.50 mm surrounded by a conducting shell of radius b = 7.50

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Answer:

The capacitance per unit length is $5.06\times10^{-11}\ F/m$

(b) is correct option.

Explanation:

Given that,

Radius a= 2.50 mm

Radius b=7.50 mm

Dielectric constant = 3.68

Potential difference = 120 V

We need to calculate charge per length for the capacitance

Using formula of charge per length

$\lambda=\dfrac{4\pi\epsilon_{0}\Delta V}{2 ln(\dfrac{r_{2}}{r_{1}})}$

Put the value into the formula

$\lambda=\dfrac{120}{9\times10^{9}\times2 ln(\dfrac{7.50\times10^{-3}}{2.50\times10^{-3}})}$

$\lambda=6.068\times10^{-9}\ C/m$

We know that,

$\lambda=\dfrac{Q}{L}$

We need to calculate the capacitance per unit length

Using formula of capacitance per unit length

$C=\dfrac{\dfrac{Q}{L}}{\Delta V}$

$C=\dfrac{6.068\times10^{-9}}{120}$

$C=5.06\times10^{-11}\ F/m$

Hence, The capacitance per unit length is $5.06\times10^{-11}\ F/m$

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3 years ago

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3 years ago

A car starts out traveling at 35 m/s. The car hits the brakes and decelerates at a rate of 3 m/s^2 for 5 seconds. What Distance

Ipatiy [6.2K]

Answer:

Time needed: 2.5 s
Distance covered: 31.3 m

Explanation:

I'll start with the distance covered while decelerating. Since you know that the initial speed of the car is 15.0 m/s, and that its final speed must by 10.0 m/s, you can use the known acceleration to determine the distance covered by

v2f=v2i−2⋅a⋅d

Isolate d on one side of the equation and solve by plugging your values

d=v2i−v2f2a

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3 years ago

What makes speed, velocity, acceleration, distance, and time different?​

What makes speed, velocity, acceleration, distance, and time different?