Answer:
I think the correct answer is B.
Answer:
17640J
Explanation:
Give mass m= 60kg
Height h =30m
Since the student is standing on the edge of a cliff , acceleration due to gravity g is 9.8m/s^2
The student’s gravitational potential energy can be found by the formula
mgh
That’s 60 x 9.8 x 30
= 17640J
If one of the four engines suddenly fail, so this means
that we only get 3 / 4 of the original force. Since force is the product of
mass and acceleration and mass is constant, therefore we get 3 / 4 of the
original acceleration.
So the remaining acceleration is:
a = (2.0 m/s^2) * (3 / 4)
<span>a = 1.5 m/s^2</span>
A star's apparent brightness is the brightness seen by humans on Earth. A star's absolute brightness is its actual brightness and does not depend on where the star is viewed from.
Answer:
the maximum deformation undergone by the spring = 47.46 cm
Explanation:
Using conservation of momentum:
where:
Then;
v = 19.375 m/s
However ; using conservation of energy to determine the maximum deformation undergone by the spring ; we have:
![\frac{1}{2} [m_Av_A^2 +m_Bv_B^2] =\frac{1}{2}[(m_A+m_B)v^2 + kx^2]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Bm_Av_A%5E2%20%2Bm_Bv_B%5E2%5D%20%3D%5Cfrac%7B1%7D%7B2%7D%5B%28m_A%2Bm_B%29v%5E2%20%2B%20kx%5E2%5D)
![[m_Av_A^2 +m_Bv_B^2] =[(m_A+m_B)v^2 + kx^2]](https://tex.z-dn.net/?f=%5Bm_Av_A%5E2%20%2Bm_Bv_B%5E2%5D%20%3D%5B%28m_A%2Bm_B%29v%5E2%20%2B%20kx%5E2%5D)
![[\frac{250*10^3}{9.81}*40^2 + \frac{550*10^3}{9.81}*10^2] =[ (\frac{800*10^3}{9.81} )*19.375^2 + 70 *10^6 \ * x^2]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B250%2A10%5E3%7D%7B9.81%7D%2A40%5E2%20%2B%20%5Cfrac%7B550%2A10%5E3%7D%7B9.81%7D%2A10%5E2%5D%20%3D%5B%20%28%5Cfrac%7B800%2A10%5E3%7D%7B9.81%7D%20%29%2A19.375%5E2%20%2B%2070%20%2A10%5E6%20%5C%20%2A%20x%5E2%5D)
x = 0.4746 m
x = 47.46 cm
Thus, the maximum deformation undergone by the spring = 47.46 cm
