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ivanzaharov [21]
2 years ago
7

Cork has a density of about 0.60 g/cm3 . Cork will partially float in water which has a density of 1.0 g/cm3 . If the piece of c

ork has a total volume of 5.0 cm3 what volume of cork is below the water
Physics
1 answer:
Fantom [35]2 years ago
4 0

Answer:

3 cm³

Explanation:

Density of the cork = 0.6 g/cm³

Density of water = 1 g/cm³

Volume of cork = 5 cm³

We all know that the formula for density is given as

Density = mass/volume,

The mass of the cork is

Mass = density * volume

Mass = 0.6 * 5

Mass = 3 gram

Given that the density is 0.6, and it is partially floating, then we can say that the volume of the cork below the water is

5 * 0.6 = 3 cm³

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A 200 kg weather rocket is loaded with 100 kg of fuel and fired straight up. It accelerates upward at 35 m/s2 for 35 s , then ru
r-ruslan [8.4K]

Answer:

T = 295.57 s

Explanation:

given,

mass of the rocket = 200 Kg

mass of the fuel = 100 Kg

acceleration = 35 m/s²

time, t = 35 s

time taken by the rocket to hit the ground, = ?

Final speed of the rocket when fuel is empty

using equation of motion

v = u + a t

v = 0 + 35 x 35

v = 1225 m/s

height of the rocket where fuel is empty

v² = u² + 2 a s

1225² = 0 + 2 x 35 x h₁

h₁ = 21437.5 m

After 35 s the rocket will be moving upward till the final velocity becomes zero.

Now, using equation of motion to find the height after 35 s

v² = u² + 2 g h₂

0² = 1225² + 2 x (-9.8) h₂

h₂ = 76562.5 m

total height = h₁ + h₂

          = 76562.5 m + 21437.5 m = 98000 m

now, time taken by before the rocket hit the ground

using equation of motion

s = u t +\dfrac{1}{2}at^2

-13500 = 1225 t -\dfrac{1}{2}\times 9.8 \times t^2

negative sign is used because the distance travel by the rocket is downward.

4.9 t² - 1225 t - 13500 = 0

t = \dfrac{-(-1225)\pm \sqrt{1225^2 - 4\times 4.9 \times (-13500)}}{2\times 4.9}

t = 260.57 s

neglecting the negative sign

total time the rocket was in air

T = t₁ + t₂

T = 35 + 260.57

T = 295.57 s

Time for which rocket was in air is equal to 295.57 s.

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