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ss7ja [257]
3 years ago
14

How would I find the average distance for this?

Physics
2 answers:
NemiM [27]3 years ago
4 0
I think you should just add all of the distances and divide it by each one of the times
Maslowich3 years ago
3 0

Answer:

Explanation:add them then divide them by 100 I think

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A gold bar contains 63.0 mol of gold, Au(s). How many atoms of gold are in the bar?
vredina [299]

Answer:

63.0 x (6.02 x 10^23) = 3.79 x 10^25 atoms of gold

Explanation:

There are 6.02 x 10^23 representative particles in a mole of any substance. Multiply it by the number of moles, and you will get the number of representative particles (atoms, molecules, formula units)

7 0
3 years ago
An airplane flies in a horizontal circle of radius 500 m at a speed of 150 m/s. If the radius were changed to 1000 m, but the sp
laila [671]

Answer:

The centripetal acceleration changed by a factor of 0.5

Explanation:

Given;

first radius of the horizontal circle, r₁ = 500 m

speed of the airplane, v = 150 m/s

second radius of the airplane, r₂ = 1000 m

Centripetal acceleration is given as;

a = \frac{v^2}{r}

At constant speed, we will have;

v^2 =ar\\\\v = \sqrt{ar}\\\\at \ constant\ v;\\\sqrt{a_1r_1} = \sqrt{a_2r_2}\\\\a_1r_1 = a_2r_2\\\\a_2 = \frac{a_1r_1}{r_2} \\\\a_2 = \frac{a_1*500}{1000}\\\\a_2 = \frac{a_1}{2} \\\\a_2 = \frac{1}{2} a_1

a₂ = 0.5a₁

Therefore, the centripetal acceleration changed by a factor of 0.5

7 0
4 years ago
The amount of dissolved oxygen in water may decrease because of the 
Elanso [62]
<span>The amount of dissolved oxygen in water may decrease because of the increase in organic matter in the water. <span>Aquatic organisms breathe and use oxygen. Large amounts of oxygen are consumed by the decomposition of bacteria (when there are large amounts of dead matter to decompose, there will be a significant number of bacteria). Examples: dead organic matter (algae), wastewater, garden waste, oils and fats, all this results in a decrease in dissolved oxygen in the water.</span></span>
8 0
3 years ago
Read 2 more answers
A toy car goes over a small ramp at a horizontal velocity of 1.21 m/s and decelerates at 0.131 m/s2 while in the air. The total
xz_007 [3.2K]
We need to considerate only the horizontal component of the motion of the toy car.

The formula for the distance in a decelerated motion is:
s = s₀ + v₀·t - 1/2·a·t²

where:
s₀ = initial position = 0
v₀ = initial velocity = 1.21 m/s
t = time elapsed = 0.342 s
a = deceleration = 0.131 m/s²

Plugging in numbers:
s = 0 + 1.21×0.342 - 0.5×0.141×(0.342)²
  = 0.406 m

Hence, the toy car traveled a distance of about 41 cm.

3 0
3 years ago
What are the characteristics of low energy waves
Ray Of Light [21]
Higher frequency,higher energy,shorter wavelength
8 0
3 years ago
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