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3 years ago

How would I find the average distance for this?

Physics

2 answers:

NemiM [27]3 years ago

4 0

I think you should just add all of the distances and divide it by each one of the times

Maslowich3 years ago

3 0

Answer:

Explanation:add them then divide them by 100 I think

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an open rectangular tank 1.0 meter wide and 2.0 meter long contains gasoline to a depth of 1.5 meters. if the height of the tank

Alekssandra [29.7K]

The maximum horizontal acceleration is solved to be 4.91 m/s^2

<u />

<h3>What is acceleration?</h3>

This is a term in physics that refers to change in velocity with time. Acceleration can be positive or negative or zero,

<u />

<u>Given data</u>

open rectangular tank

width = 1.0 m

length = 2.0 m

gasoline depth level = 1.5 m

height of the tank = 2.0 m

<h3>How to solve for maximum horizontal acceleration</h3>

lets represent the volume with x, y, and z such that z corresponds to height, y corresponds to wide or width, and x corresponds to length.

dz / dy = - ay / ( g + az )

where

ay = acceleration in the y direction

az = acceleration in the z direction which is equal to zero

g = acceleration due to gravity

plugging in az = 0

dz / dy = - ay / ( g )

ay = - ( dz / dy ) * g

to prevent spilling

dz / dy = - ( 1.5 - 1 ) / 1

dz / dy = - 0.5

ay = - ( - 0.5 ) * 9.81

ay = 4.91 meters per second square

Hence the maximum horizontal acceleration is solved to be 4.91 m/s^2

Read more on acceleration here: brainly.com/question/605631

#SPJ1

7 0

2 years ago

A ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally aw

pshichka [43]

Answer:

44.3 m/s

Explanation:

Given that a ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally away from and below the point of release.

What is the magnitude of its velocity just before it strikes the ground ?

The parameters given are:

Height H = 100m

Since the ball is thrown from a top of a building, initial velocity U = 0

Let g = 9.8m/s^2

Using third equation of motion

V^2 = U^2 + 2gH

Substitute all the parameters into the formula

V^2 = 2 × 9.8 × 100

V^2 = 200 × 9.8

V^2 = 1960

V = 44.27 m/s

Therefore, the magnitude of its velocity just before it strikes the ground is 44.3 m/s approximately

6 0

3 years ago

A sample of polonium-210 was left for 414 days.

jenyasd209 [6]

Answer:

PO(1) = PO(0) / 2 1 refers to 1 half life of PO(0)

PO(2) = PO(1) / 2 = P(0) / 4 amount of PO left after 2 half-lives

PO(3) = PO(2) / 2 = PO(0) / 8 amount of PO left after 3 half-lives

414 da / 138 da = 3 3 half-lives pass in 414 da

PO(0) = 8 PO(3) = 8 * 1.45E-4 g = 1.16E-3 g = .00116 g after 414 days

6 0

3 years ago

A stone is thrown vertically upward with a speed of 12m/s from the edge of a cliff 70 m high (a) How much later it reaches the b

jonny [76]

Answer

given,

vertical speed of stone,v = 12 m/s

height of the cliff = 70 m

a) time taken by the stone to reach at the bottom of the cliff

We know that,

S = u t + 1/2 a t²

- 70 = 12 t - 0.5 x 9.8 t²

4.9 t² - 12 t - 70 = 0

solving the equation

t = 5.2 s (neglecting the negative value)

b) again using equation of motion

v = u + a t

v = 12 - 9.8 x 5.2

v = -38.96 m/s

ignoring the negative sign

magnitude of velocity is equal to 38.96 m/s

c) total distance travel by the stone

vertical distance covered by the stone

v² = u² + 2 g h

0 = 12² - 2 x 9.8 x h

h = 7.34 m

to reach the stone to the same level distance travel be doubled.

Total distance travel by the stone

H = h + h + 70

H = 7.34 x 2 + 70

H = 84.7 m.

8 0

3 years ago

The element sodium has an atomic number of 11 and a mass number of 23. how many protons, neutrons, and electrons does one atom c

Julli [10]

I think it has 11 but i don't really know for sure.Correct me if i'm wrong.

8 0

4 years ago