Distance traveled by the ball is given by

here we know that
speed = 20 m/s
times = 0.25 s
now we have


so ball will travel 5 m distance in the given interval of time
Answer:
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Explanation:
Answer:
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- Frequency ( f ) = 7 Hertz
- Wavelength ( λ ) = 42m
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~Plug the known values and then multiply!
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- Frequency ( f ) : The number of complete waves , set up in a medium in one second is called frequency of the wave. The SI unit of frequency is Hertz ( Hz ). For example : if a sound wave completes 15 compressions and 15 rarefactions in one second , it's frequency is 15 Hz.
- Wavelength ( λ ) : The distance between two consecutive troughs or crests in a transverse wave or the distance between two consecutive compressions or rarefactions in a longitudinal wave us called wavelength. It is the distance travelled by a wave in a time equal to it's time period. It's SI unit is metre ( m ).
- Wave velocity ( v ) : The velocity with which a wave propagates in a medium is called wave velocity. It's SI unit is m/s.
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Answer:
Pressure = 5 x 10⁶ Pa
Explanation:
Given:
Height of building = 512 m
Find:
Pressure
Computation:
P2 = P1+dgh
P2 = 1 + (1000)(9.8)(512)
P2 = 51.2 atm
Pressure = 5 x 10⁶ Pa
Answer:
Flight path angle= 15.12°, maximum range= 5.29× 10*6 km
Explanation:
u= 7200m/s, H= 180km= 180000m
Recall that
Maximum height, H= (u*2sin*2∆)/2g
180000= (7200×7200sin*2∆)/2×9.8
(18000×2×98)/7200×7200= sin*2∆
Sin∆= 0.2609
∆= 15.12°
Maximum range, R= u*2/g
(7200×7200)/9.8
= 5289795.92km
= 5.29× 10*6 km