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ss7ja [257]
2 years ago
14

How would I find the average distance for this?

Physics
2 answers:
NemiM [27]2 years ago
4 0
I think you should just add all of the distances and divide it by each one of the times
Maslowich2 years ago
3 0

Answer:

Explanation:add them then divide them by 100 I think

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A baseball leaves a bat with a horizontal velocity of 20 m/s. In a time of 0.25 s, How far will it have traveled horizontally?
Maurinko [17]

Distance traveled by the ball is given by

distance = speed \times time

here we know that

speed = 20 m/s

times = 0.25 s

now we have

distance = 20 \times 0.25

distance = 5 m

so ball will travel 5 m distance in the given interval of time

6 0
3 years ago
Suppose multiple stations are connected in wired network where CSMA/CD implemented. Among them, station A wants to communicate w
anastassius [24]

Answer:

bro i think ur from the uni of arid agriculture rawalpindi and today is your networking paper

Explanation:

6 0
3 years ago
What is the speed of a wave if it has a wavelength of<br> 42 m and a frequency of 7 hertz?
Nimfa-mama [501]

Answer:

♕ \large{ \red{ \tt{Step - By - Step \: Explanation}}}

☃ \underline{ \underline{ \blue{ \large{ \tt{G \: I \: V \: E\: N}}}}} :

  • Frequency ( f ) = 7 Hertz
  • Wavelength ( λ ) = 42m

♨ \underline {\underline{ \orange{ \large{ \tt{T \: O \:  \: F \: I \: N\: D}}}} }:

  • Wave velocity ( v )

☄ \underline{ \underline{ \large{ \pink{ \tt{S\: O \: L \: U \: T\: I \: O \: N}}}}}:

✧ \red{ \boxed{ \large{ \purple{ \sf{Wave \: velocity(v) = Frequency(f) \times Wavelength(λ)}}}}}

~Plug the known values and then multiply!

↦ \large{ \tt{7  \times 42}}

↦ \boxed{ \boxed{ \large{ \bold{ \tt{294 \: m {s}^ {- 1} }}}}}

☥ \large{ \boxed{ \boxed{ \large{ \tt{Our \: Final \: Answer :  \underline{ \large{ \tt{294 \: m {s}^{ - 1}}}}}}}}}

---------------------------------------------------------------

❁ \underline{ \large{  \red{ \tt{D\: E\: T \: A \: I \: L\: E \: D \:  \: I\: N \: F \: O}}}} :

  • Frequency ( f ) : The number of complete waves , set up in a medium in one second is called frequency of the wave. The SI unit of frequency is Hertz ( Hz ). For example : if a sound wave completes 15 compressions and 15 rarefactions in one second , it's frequency is 15 Hz.

  • Wavelength ( λ ) : The distance between two consecutive troughs or crests in a transverse wave or the distance between two consecutive compressions or rarefactions in a longitudinal wave us called wavelength. It is the distance travelled by a wave in a time equal to it's time period. It's SI unit is metre ( m ).

  • Wave velocity ( v ) : The velocity with which a wave propagates in a medium is called wave velocity. It's SI unit is m/s.

# KILL : Excuses

KISS : Opportunities

MARRY : Goals

♪ Hope I helped! ♡

☂ Have a wonderful day / night ! ツ

✎ \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}} ✔

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

4 0
3 years ago
A building is 512 m high. What must be the minimum water pressure in a pipe at ground level in order to get water out of a tap i
vivado [14]

Answer:

Pressure =  5 x 10⁶ Pa

Explanation:

Given:

Height of building = 512 m

Find:

Pressure

Computation:

P2 = P1+dgh

P2 = 1 + (1000)(9.8)(512)

P2 = 51.2 atm

Pressure =  5 x 10⁶ Pa

6 0
3 years ago
DETERMINE THE LAUNCH ELEVATION AND MAXIMUM RANGE: The test vehicle should obtain a burnout velocity of 7200 m/s at 180 km altitu
fenix001 [56]

Answer:

Flight path angle= 15.12°, maximum range= 5.29× 10*6 km

Explanation:

u= 7200m/s, H= 180km= 180000m

Recall that

Maximum height, H= (u*2sin*2∆)/2g

180000= (7200×7200sin*2∆)/2×9.8

(18000×2×98)/7200×7200= sin*2∆

Sin∆= 0.2609

∆= 15.12°

Maximum range, R= u*2/g

(7200×7200)/9.8

= 5289795.92km

= 5.29× 10*6 km

8 0
3 years ago
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