Why one of the three structures for c2h2cl2 is nonpolar?
1 answer:
Below are the three possible isomers of chemical formula C₂H₂Cl₂. Among these three isomers the <em>trans</em>-1,2-dichloroethene is non-polar while, remaining two are polar.
Reason:
Reason for this is dipole moment. In case of <em>cis</em>-1,2-dichloroethene and 1,1-dichloroethene, the vectors are reinforcing each other perpendicularly to double bond, hence, giving a net dipole moment and making these two isomers polar in nature.
While, in case of <em>trans</em> isomer the two vectors are cancelling each other as the two chlorine atoms are in opposite directions. Hence, the net dipole moment is zero in this case. So, it is non-polar in nature.
Reason:
Reason for this is dipole moment. In case of <em>cis</em>-1,2-dichloroethene and 1,1-dichloroethene, the vectors are reinforcing each other perpendicularly to double bond, hence, giving a net dipole moment and making these two isomers polar in nature.
While, in case of <em>trans</em> isomer the two vectors are cancelling each other as the two chlorine atoms are in opposite directions. Hence, the net dipole moment is zero in this case. So, it is non-polar in nature.
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Answer: The volume of the oxygen gas at a pressure of 2.50 atm will be 1.44 L
At constant temperature, the volume of a fixed mass of gas is inversely proportional to the pressure it exerts, then
PV = c
Thus, if the pressure increases, the volume decreases, and if the pressure decreases, the volume increases.
It is not necessary to know the exact value of the constant c to be able to use this law since for a fixed amount of gas at constant temperature, it is satisfied that,
P₁V₁ = P₂V₂
Where P₁ and P₂ as well as V₁ and V₂ correspond to pressures and volumes for two different states of the gas in question.
In this case the first oxygen gas state corresponds to P₁ = 1.00 atm and V₁ = 3.60 L while the second state would be P₂ = 2.50 atm and V₂ = y. Substituting in the previous equation,
1.00 atm x 3.60 L = 2.50 atm x y
We cleared y to find V₂,
V₂ = y = = 1.44 L
Then, <u>the volume of the oxygen gas at a pressure of 2.50 atm will be 1.44 L</u>
Answer:
(1) addition of HBr to 2-methyl-2-pentene
Explanation:
In this case, we will have the formation of a <u>carbocation</u> for each molecule. For molecule 1 we will have a <u>tertiary carbocation</u> and for molecule 2 we will have a <u>secondary carbocation</u>.
Therefore the <u>most stable carbocation</u> is the one produced by the 2-methyl-2-pentene. So, this molecule would react faster than 4-methyl-1-pentene. (See figure)
