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bazaltina [42]
1 year ago
5

Simón Bolívar and José de San Martín are figures associated with what event?

Chemistry
1 answer:
Jobisdone [24]1 year ago
5 0

The event is South American independence. <u>Option D.</u>

<u />

By 1820, royalist Peru was an isolated outpost of Spanish influence. San Martin liberated Chile and Argentina to the south while Simon Bolivar and Antonio Jose de Sucre liberated Ecuador Colombia, and Venezuela to the north leaving only Peru and present-day Bolivia under Spanish control.

Simon Bolivar wrote two of his political treatises. The Manifesto de Cartagena Declaration of Cartagena and Carta de Jamaica Letters from Jamaica told the people of South America that Spain urged them to rebel against their colonial rule. Simon Bolivar is a Creole who grew up in a wealthy family. Bolivar devoted his time and effort to fight for Venezuela's independence from Spain. Bolivar was inspired by the Enlightenment ideas of John Locke.

Learn more about Simon Bolivar here:-brainly.com/question/1402690

#SPJ1

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What is the mass of 2M H2SO4 in a 50ml of solution ​
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Answer:

It is given in the question that molarity of the sulphuric acid is 2M, the volume of the sulphuric acid is 20 mL, the volume of the solution is 1`L.

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3 years ago
What has to be true about available resources for competition to exist?
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Answer:

Limited

Explanation:

For competition to exist within a population or between population, shared or common resources that organisms holds very important must be very limited and scared.

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8 0
3 years ago
An atom that has one or two valence electrons is most likely to be - Nonreactive only
meriva

Answer:

C) Highly reactive

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4 0
3 years ago
A science teacher has a supply of 50% sugar solution and a supply of 80% sugar solution. How much of each solution should the te
Monica [59]
You can establish a system of two equation with two variables.

Varibles are:
V1 = volume of the 50% sugar solution
V2 = volumen of the 80% sugar solution

Equations:
Balance of sugar:

Sugar from 50% solution: 0.5*V1
Sugar from 80% solution: 0.8*V2
Sugar in the final solution (mix): 0.6 * 105 = 63

1) 0.5V1 + 0.8V2 = 63

Final volume = volume of 50% solution + volume of 80% solution

2) V1 + V2 = 105

From (2) V1 = 105 - V2

Substitue in (1)

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52.5 - 0.5V2 + 0.8V2 = 63

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0.3 V2 = 10.5

V2 = 10.5/0.3
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V1 = 105 - 35 = 70 mL

Answer: 70 mL of the 50% solution and 35 mL of the 80% solution.
5 0
3 years ago
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