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2 years ago

How many electrons are in the highest occupied energy level of a neutral chlorine atom?

Chemistry

2 answers:

tino4ka555 [31]2 years ago

5 0

There are seven electrons

goldenfox [79]2 years ago

4 0

There would be seven electrons :)

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Tin was among the first metals used by humans. Elemental tin is produced by heating tin(IV) oxide, the principal ore of tin, wit

insens350 [35]

Answer: The coefficient of carbon in the chemical reaction is 1.

Explanation:

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

The chemical equation for the reaction of tin (IV) oxide and carbon follows:

$SnO_2+C\rightarrow Sn+CO_2$

By Stoichiometry of the reaction:

1 mole of tin (IV) oxide reacts with carbon to produce 1 mole of elemental tin and carbon dioxide.

Hence, the coefficient of carbon in the chemical reaction is 1.

4 0

3 years ago

Ag + HCl --> ? a) No reaction b) AgCl + H2 c) AgCl + H2O PLEASE HELP

Volgvan

Answer:

AgCl + H2 - Chemical Equation Balancer.

8 0

3 years ago

Read 2 more answers

What is nuclear fission

swat32

Nuclear fission is the process of which a large nucleus splits into two smaller nuclei with the release of energy and neutron. In simpler words, nuclear fission is the process in which a nucleus is split into two smaller fragments or pieces (nuclei) and so energy and neutrons are released. The resulting pieces of this fission process have less combined mass than the original piece (nucleus) and the missing was is converted into nuclear energy.

5 0

3 years ago

Read 2 more answers

There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with

grandymaker [24]

$\text{Hg} \text{O}$ and $\text{Hg}_{2} \text{O}$ .

Assuming complete decomposition of both samples,

$m(\text{Hg}) = m(\text{residure})$
$m(\text{O}) = m(\text{loss})$

First compound:

$m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g$
$m(\text{Hg}) = m(\text{residure}) = 0.6018 \; g$

$n = m/M$ ; $0.6498 \; g$ of the first compound would contain

$n(\text{O atoms}) = 0.048 \; g / 16 \; g \cdot mol^{-1}= 0.003 \; mol$
$n(\text{Hg atoms}) = 0.6018 \; g / 200.58 \; g \cdot mol^{-1}= 0.003 \; mol$

Oxygen and mercury atoms seemingly exist in the first compound at a $1:1$ ratio; thus the empirical formula for this compound would be $\text{Hg} \text{O}$ where the subscript "1" is omitted.

Similarly, for the second compound

$m(\text{O}) = m(\text{loss}) = 0.016 \; g$
$m(\text{Hg}) = m(\text{residure}) = 0.4172 - 0.016 = 0.4012 \; g$

$n = m/M$ ; $0.4172 \; g$ of the first compound would contain

$n(\text{O atoms}) = 0.016 \; g / 16 \; g \cdot mol^{-1}= 0.001 \; mol$
$n(\text{Hg atoms}) = 0.4012 \; g / 200.58 \; g \cdot mol^{-1}= 0.002 \; mol$

$n(\text{Hg}) : n(\text{O}) \approx 2:1$ and therefore the empirical formula

$\text{Hg}_{2} \text{O}$ .

8 0

3 years ago

Given the following chemical reaction: 2 O2 + CH4 CO2 + 2 H2O What mass of oxygen is required to completely react with 20 grams

Jobisdone [24]

The chemical equation is:
CH₄ + 2O₂ → CO₂ + 2H₂O

First, we calculate the moles of methane present using:
Moles = mass / molecular mass
Moles = 20 / 16
Moles = 1.25

Next, we may observe from the chemical equation that the molar ratio between methane and oxygen is 1 : 2
So the moles of oxygen required are 2 x 1.25
2.5 moles of oxygen required

Mass = moles * molecular mass
Mass = 2.5 * 32
Moles = 80

C. 80 grams O₂

4 0

3 years ago