Complete question:
On the package for a certain brand of spinach seeds there is a guarantee that, if the printed instructions are followed, 63% of planted seeds will germinate. A random sample of 9 seeds is chosen. If these seeds are planted according to the instructions, find the probability that 4 of them germinate.
Answer:
Step-by-step explanation:
Given
--- proportion that germinates
Required
P(x = 4)
This question follows a binomial distribution:
When x = 4;
Answer:
C
Step-by-step explanation:
Since the equation is the same on both sides, you can plug any number in and it will be true.
To solve this you must use a proportion like so...
94 is a percent and percent's are always taken out of the 100. This means that one proportion will have 94 as the part and 100 as the whole
We want to know how many ounces of copper is in a 9.15 ounce bar that contains 94% copper. This means 9.15 is the whole and the unknown ounces of copper (let's make this x) is the part.
Here is your proportion:
Now you must cross multiply
x*100 = 9.15*94
100x = 860.1
To isolate x divide 100 to both sides
100x/100 = 860.1/100
8.601 = x
This means that a 9.15 ounce bar is composed of 8.601 ounces of copper
Hope this helped!
~Just a girl in love with Shawn Mendes