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3 years ago

I can't find the answer for number 9/10 pleas help

Chemistry

2 answers:

kondaur [170]3 years ago

8 0

(10)an object will continue to travel at a constant speed unless acted by an unbalanced force according to newtons second law every force acted on a body has a equal and opposite reaction so the speed and the direction of the object will change.

(9) balanced force (i think so )

hope this is what you needed the 10th one is for understanding you can shorten it after reading and i think what i have written is not wrong :P:P:P;p:P:):):):D=) for the ninth one i am not sure but i think so :P:)=)

7nadin3 [17]3 years ago

6 0

It should be : balance forces

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As AgNO3 dissolves how does the temperature of the solution change

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Answer:

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Explanation:

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A 73.6 g sample of aluminum is heated to 95.0°C and dropped into 100.0 g of water at 20.0°C. If the resulting temperature of the

Softa [21]

Answer:

The specific heat of aluminium is 0.875 J/g°C

Explanation:

Step 1: Data given

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Mass of water = 100.0 grams

Initial temperature of water = 20.0 °C

Final temperature of water and aluminium = 30.0 °C

The specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of aluminium

Q gained = Q lost

Qwater = -Qaluminium

Q = m*c*ΔT

m(aluminium) * c(aluminium) * ΔT(aluminium) = - m(water) * c(water) * ΔT(aluminium)

⇒ mass of aluminium = 73.6 grams

⇒ c(aluminium) = TO BE DETERMINED

⇒ ΔT(aluminium) = The change of temperature = T2 - T1 = 30 .0 °C - 95.0 °C = -65.0°C

⇒ mass of water = 100.0 grams

⇒ c(water ) = The specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature of water = T2 - T1 = 30.0 - 20.0 = 10.0 °C

73.6g * c(aluminium) * -65.0 °C = 100.0g * 4.184 J/g°C * 10.0°C

-4784 * c(aluminium) = -4184

c(aluminium) = 0.875 J /g°C

The specific heat of aluminium is 0.875 J/g°C

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3 years ago

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fredd [130]

Answer:

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Explanation:

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MrMuchimi

Answer:

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3 years ago