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777dan777 [17]
3 years ago
5

I can't find the answer for number 9/10 pleas help

Chemistry
2 answers:
kondaur [170]3 years ago
8 0
(10)an object  will continue  to travel at a constant speed unless acted by an unbalanced  force  according to newtons second law every force acted on a body has a equal and opposite reaction so the speed and the direction of the object will change.

(9) balanced force (i think so )

hope this is what you needed the 10th one is for understanding you can shorten it after reading and i think what i have written is not wrong :P:P:P;p:P:):):):D=) for the ninth one i am not sure but i think so :P:)=)


7nadin3 [17]3 years ago
6 0
It should be : balance forces
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PLEASE HELP ASAP I NEED IT
Lapatulllka [165]

the answer is true the first one

3 0
3 years ago
Different kinds of wood have different densities. The density of american white oak wood is generally 0.77 g/cm3. If Jim grabs a
mixas84 [53]

Answer:

m= 29.645 g

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

density of wood = 0.77 g/cm³

volume= 38.5 cm³

mass= ?

Solution:

d= m/v

m= d × v

m= 0.77 g/cm³× 38.5 cm³

m= 29.645 g

7 0
3 years ago
Enter your answer in the provided box.
Lina20 [59]

Answer:

5.06atm

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (Litres)

V2 = final volume (Litres)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 1.34 atm

P2 = ?

V1 = 5.48 L

V2 = 1.32 L

T1 = 61 °C = 61 + 273 = 334K

T2 = 31 °C = 31 + 273 = 304K

Using P1V1/T1 = P2V2/T2

1.34 × 5.48/334 = P2 × 1.32/304

7.34/334 = 1.32P2/304

Cross multiply

334 × 1.32P2 = 304 × 7.34

440.88P2 = 2231.36

P2 = 2231.36/440.88

P2 = 5.06

The final pressure is 5.06atm

6 0
2 years ago
2. Calculate the atomic mass of an element that has two isotopes, each with 50.00% abundance. One isotope has a mass of 63.00 am
melamori03 [73]

Answer:

The atomic mass of element is 65.5 amu.

Explanation:

Given data:

Abundance of X-63 = 50.000%

Atomic mass of  X-63 = 63.00 amu

Atomic mass of X-68 = 68.00 amu

Atomic mass of element = ?

Solution:

Abundance of X-68 = 100-50 = 50%

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (50×63)+(50×68) /100

Average atomic mass =  3150 + 3400 / 100

Average atomic mass  = 6550 / 100

Average atomic mass = 65.5 amu.

The atomic mass of element is 65.5 amu.

7 0
3 years ago
HELP PLEASE ANSWER PLEASE ITS URGENT!!<br><br> -unnecessary comments will be reported.
Verizon [17]

Answer:

19. 1, 2, 3, 4, 5, 6, 7, 8

20. Li=1+, Be=2+, B=3+, C=4+

21. N=3-, O=2-, F=1-

Explanation:

8 0
3 years ago
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