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3 years ago

Your family is driving across the country to the Grand Canyon what type pollution is your car producing

Chemistry

1 answer:

IgorLugansk [536]3 years ago

8 0

Answer:

The correct answer would be Air Pollution, and Mobile Pollution.

Explanation:

Your family is driving across the country to the Grand Canyon, Air Pollution or Mobile Pollution is produced by your car.

Air pollution is the pollution generated by the Gas emission, Chemical emission, Car Emission, Dust, etc. This pollution consists of solid particles and gases. Air Pollution is very dangerous as it directly affects the Ozone layer.

As the car is moving, so the car is generating the Air pollution, which is considered a mobile source, because car is travelling from one place to another and emitting air pollution where ever it is going.

You might be interested in

Which sphere is dependent on all the other spheres in order to exist?

egoroff_w [7]

Answer:

biosphere

Explanation:

Living things need water (hydrosphere), chemicals from the atmosphere, and nutrients gained by eating things in the biosphere.

6 0

3 years ago

Determining Density and Using Density to Determine Volume or Mass

Shalnov [3]

corrected question:

Determining Density and Using Density to Determine Volume or Mass

(a) Calculate the density of mercury if 1.00 × 10 g occupies a volume of 7.36 cm³

(b) Calculate the volume of 65.0 g of liquid methanol (wood alcohol) if its density is 0.791 g/mL.

(d) Calculate the density of a 374.5-g sample of copper if it has a volume of 41.8 cm³ A student needs 15.0 g of ethanol for an experiment. If the density of ethanol is 0.789 g/mL, how many milliliters of ethanol are needed? What is the mass, in grams, of 25.0 mL of mercury (density = 13.6 g/mL)?

Answer:

density = $\frac{mass}{volume}$

ρ=m/v ,m=ρv, v=m/ρ

(a)m=1*10g , v=7.36cm³

ρ=10/7.36 =1.36g/cm³

(b) m=65g, ρ=0.791 g/mL.

v= 65/0.791 =82.17g/mL

m=19..32*8=154.56g/cm³

(d) mass of copper=374.5g , v=41.8cm³

ρ=374.5/41.8 =8.96g/cm³

mass of ethanol=15g, density of ethanol=0.789g/mL

v=15/0.789 =19.01mL

volume of mecury=25mL, density of mercury=13.6g/mL

m=25*13.6=340g

4 0

3 years ago

I what process does a solid change directly into a vapor

Marina86 [1]

Answer:

solid change directly into a vapor in the process known simply as freezing

7 0

3 years ago

En un recipiente colocamos unos cubos de hielo luego tapamos y observamos que sucede despues de un tiempo

SSSSS [86.1K]

Three questions come along with the given statement. It is in Spanish language:

a) Por qué se humedeció la parte exterior del frasco?

b) Por qué el hielo disminuyó su volumen y ahora es agua?

c) Por qué puede haber agua en el exterior?

These are the three answers (in English).

First question:

a) Por qué se humedeció la parte exterior del frasco?

The question is Why did the outside of the bottle get wet?

Answer:

The outside of the bottle get wet because the ice cubes cooled the walls of the bottle, so the air surrounding the bottle also cooled.

The air contains humidity (water) in gas phase. The hotter the air the more the amount of humidity it can retain, the cooler the air the less the amount of humidity it can retain.

Then, when the air close to the walls of the bootle got cooler some of the water in the air became liquid and those are the drops of water that you see in the outside of the bottle.

Second question

b) Por qué el hielo disminuyó su volumen y ahora es agua?

The question is Why did the ice diminish its volume and now it is water?

Answer:

The ice diminished its volume and now it is water, becasue the ice, which is cooler than the surroundings, received heat energy (from the surroundings) and then its temperature increased. At some moment, this temperature reached the melting point of the ice (water) and it started to become liquid.

Third question

c) Por qué puede haber agua en el exterior?

The question is: Why can there be water outside?

Answer:

The water outside is outside since the beginning: it is in the air. You do not see it because it is gas state. When the air close to the walss of the bottle got cooler, part of the water in the air became liquid.

4 0

3 years ago

Given that cao(s) + h2o(l) → ca(oh)2(s), δh°rxn = –64.8 kj/mol, how many grams of cao must react in order to liberate 525 kj of

USPshnik [31]

Answer:

454.3 g.

Explanation:

From the given data:

1.0 mol of CaO liberates → – 64.8 kJ.

??? mol of CaO liberates → - 525 kJ.

∴ The no. of moles needed = (1.0 mol)(- 525 kJ)/(- 64.8 kJ) = 8.1 mol.

<em>∴ The no. of grams of CaO needed = no. of moles x molar mass</em> = (8.1 mol)(56.077 g/mol) = <em>454.3 g.</em>

8 0

3 years ago