Step-by-step explanation:
We have xy = 28, x² + y² = 65 and x³ + y³ = 407.
Since (x + y)(x² - xy + y²) = x³ + y³,
x + y = (x³ + y³)/(x² + y² - xy)
= (407) / [(65) - (28)]
= 407 / 37
= 11.
Hence the sum of the numbers is 11.
It's the absolute value which is 8
X:{a, b, c}, because the numbers(or letters in this problem) cannot repeat.
I think eight because if you add those days together they will play again in eight days so that they play on the same day.
Sorry if I got it wrong I tried and that's what counts, right?
