Different densities have to have a reason - different pressure and/or humidity etc. If there is a different pressure, there is a mechanical force that preserves the pressure difference: think about the cyclones that have a lower pressure in the center. The cyclones rotate in the right direction and the cyclone may be preserved by the Coriolis force.
If the two air masses differ by humidity, the mixing will almost always lead to precipitation - which includes a phase transition for water etc. It's because the vapor from the more humid air mass gets condensed under the conditions of the other. You get some rain. In general, intense precipitation, thunderstorms, and other visible isolated weather events are linked to weather fronts.
At any rate, a mixing of two air masses is a nontrivial, violent process in general. That's why the boundary is called a "front". In the military jargon, a front is the contested frontier of a conflict. So your idea that the air masses could mix quickly and peacefully - whatever you exactly mean quantitatively - either neglects the inertia of the air, a relatively low diffusion coefficient, a low thermal conductivity, and/or high latent heat of water vapor. A front is something that didn't disappear within minutes so pretty much tautologically, there must be forces that make such a quick disappearance impossible.
Answer:
upthrust or BUOYANT FORCE =Vdg
volume=LWH
upthrust=(4cm×5cm×2cm)×1g/cm²×g
upthrust=40cm³×1g/cm³×g
upthrust=40gf or 0.04kg×10m/s²=0.4N
weight of the displaced liquid is upthrust.
so mass=40g or 0.04kg
upthrust=40gf or 0.4Nand mass of the displaced liquid=40g or 0.04kg
please mark brainliest, hope it helped
As weight =w =mg
g= gravitational acceleration on mercury = 3.7m/sec2
Mass of person =m= 70 kg
So w =(70kg)(3.7m/sec2)
w= 259 kgm/sec2
W= 259 N
Answer:
Explanation:
Given
Distance between Pluto and sun is 39.1 times more than the distance between earth and sun
According to Kepler's Law
![T^2=kR^3](https://tex.z-dn.net/?f=T%5E2%3DkR%5E3)
where k=constant
T=time period
R=Radius of orbit
Suppose
is the radius of orbit of earth and sun
so Distance between Pluto and sun is ![R_2=39.1\cdot R_1](https://tex.z-dn.net/?f=R_2%3D39.1%5Ccdot%20R_1)
and
is the time period corresponding to
and R_2[/tex]
![(T_1)^2=k(R_1)^3---1](https://tex.z-dn.net/?f=%28T_1%29%5E2%3Dk%28R_1%29%5E3---1)
![(T_2)^2=k(R_2)^3---2](https://tex.z-dn.net/?f=%28T_2%29%5E2%3Dk%28R_2%29%5E3---2)
divide 1 and 2
![(\frac{365}{T_2})^2=(\frac{R_1}{39.1})^3](https://tex.z-dn.net/?f=%28%5Cfrac%7B365%7D%7BT_2%7D%29%5E2%3D%28%5Cfrac%7BR_1%7D%7B39.1%7D%29%5E3)
![T_2^2=365^2\times 39.1^3](https://tex.z-dn.net/?f=T_2%5E2%3D365%5E2%5Ctimes%2039.1%5E3)