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SOVA2 [1]
3 years ago
13

Ralph is also swinging at the park. He has a mass of 72.6 kg, and his maximum velocity at the lowest point in his swing is 7.3 m

/s. What is Ralph’s maximum kinetic energy? Hint: Kinetic Energy = 1/2 Mass x Velocity-squared
Physics
1 answer:
pashok25 [27]3 years ago
4 0
Bsbsb s sbsb sbsbbsbdb
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Future space rockets might propel themselves by firing laser beams, rather than exhaust gases, out the back. The acceleration wo
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Answer:

Acceleration = 0.0282 m/s^2

Distance = 13.98 * 10^12 m

Explanation:

we will apply the energy theorem

work done = ΔK.E ( change in Kinetic energy )  ---- ( 1 )

<em>where :</em>

work done = p * t

                  = 15 * 10^6 watts * ( 1 year ) = 473040000 * 10^6 J

( note : convert 1 year to seconds )

and ΔK.E = 1/2 mVf^2   given ; m = 1200 kg  and initial V = 0

<u>back to equation 1 </u>

473040000 * 10^6  = 1/2 mv^2

Vf^2 = 2(473040000 * 10^6 ) / 1200

∴ Vf = 887918.92 m/s

<u>i) Determine how fast the rocket is ( acceleration of the rocket )</u>

a = Vf / t

  = 887918.92 / ( 1 year )

  = 0.0282 m/s^2

<u>ii) determine distance travelled by rocket </u>

Vf^2 - Vi^2 = 2as

Vi = 0

hence ; Vf^2 = 2as

s ( distance ) =  Vf^2 / ( 2a )

                     = ( 887918.92 )^2 / ( 2 * 0.0282 )

                    = 13.98 * 10^12 m

8 0
3 years ago
(a) On the axes below, sketch the graphs of the horizontal and vertical components of the sphere’s velocity as a function of tim
jeka94

Answer:

Two identical spheres are released from a device at time t = 0 from the same ... Sphere A has no initial velocity and falls straight down. ... (b) On the axes below, sketch and label a graph of the horizontal component of the velocity of sphere A and of sphere B as a function of time. ... Which ball has the greater vertical velocity

Explanation:

4 0
2 years ago
The process of changing the energy of a system by means of force. Force * Diatance
Dmitry_Shevchenko [17]
This is known as work
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You lift a large bag of flour from the floor to a 2.5m high counter, doing 400J of work in 2 seconds. How much force did you app
oksian1 [2.3K]
<h2>The man have to apply force of 160 N</h2>

Explanation:

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The work done can be found by relation  W = mg x h

Thus mg = \frac{W}{h} = \frac{400}{2.5} =  160 N

Therefore the man have to apply the force of 160 N

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