Answer: 12.0 m/s^2
Explanation:
Let be the angular acceleration of the end of the rod
Taking torque about the link, we have:
Torque is also given in terms of moment of inertia of the rod and its angular acceleration i.e.
From equations (i) and (ii) we have:
The acceleration of the end of the rod farthest from the link is given by:
Answer:
(a):
(b):
(c):
(d):
(e):
Explanation:
Given, the position of the particle along the x axis is
The units of terms and
should also be same as that of x, i.e., meters.
The unit of t is seconds.
(a):
Unit of
Therefore, unit of
(b):
Unit of
Therefore, unit of
(c):
The velocity v and the position x of a particle are related as
(d):
The acceleration a and the velocity v of the particle is related as
(e):
The particle attains maximum x at, let's say, , when the following two conditions are fulfilled:
Applying both these conditions,
For ,
Since, c is a positive constant therefore, for ,
Thus, particle does not reach its maximum value at
For ,
Here,
Thus, the particle reach its maximum x value at time