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dybincka [34]
2 years ago
7

When a vehicle travels at a steady speed the driving force and the

Physics
1 answer:
Ivanshal [37]2 years ago
3 0

Answer:

.......

Must be equal

Explanation:

..

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Suppose you found a mineral crystal that looked like topaz. what two minerals could you use in a scratch test to help determine
Vesna [10]
The two most important minerals you need to do the test are <span>Corundum and quartz. You use that to do scratch test</span>
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3 years ago
Describe the rules for collecting evidence against a defendant
nataly862011 [7]
In a civil case discovery is the process by witch   the plentiful and the defendant exchange information to prove the case or defendant against the accusation. The rules for discovery are usually  the stipulate the request of documents that are reasonable but in an attempt to prove wrongful  termination.The defendant could  ask to turn over the preference review for the past ten years.

Tried to simplify this as little as I could hope it helped  
3 0
3 years ago
A straight wire of length 0.56 m carries a conventional current of 0.4 amperes. What is the magnitude of the magnetic field made
djverab [1.8K]

Answer:

The magnitude of the magnetic field made by current in the wire is 3.064 x 10⁻⁶ T.

Explanation:

Given;

length of the straight wire, L = 0.56 m

conventional current, I = 0.4 A

distance of magnetic field from the wire, r = 2.6 cm = 0.026 m

To determine magnitude of magnetic field made by current in the wire, we will apply Bio-Savart Law;

B = \frac{\mu_o}{4\pi r} \frac{LI}{\sqrt{r^2 +(L/2)^2} } \\\\B = \frac{4\pi *10^{-7}}{4\pi *0.026} \frac{0.56*0.4}{\sqrt{(0.026)^2 +(0.56/2)^2} }\\\\B = 3.846*10^{-6}(0.7966)\\\\B = 3.064*10^{-6} \ T

Therefore, the magnitude of the magnetic field made by current in the wire is 3.064 x 10⁻⁶ T.

3 0
3 years ago
A proton moves with a speed of 1.17 105 m/s through Earth's magnetic field, which has a value of 50.0 µT at a particular locatio
vlabodo [156]

a) Southward you need to apply right hand rule. If you close your hand to the east, your thumb will indicate south.

b) Given the equation for Magnetic Force

F= qVB

Replacing

F= (1.16*10^{-19})(1.17*10^5)(50*10^{-6})

F=9.36*10^{-19}

c) Given the second Newton's Law by

F_g = 1.67*10^{-27}*9.81

F_g = 1.64*10^{-26}

Given the electric force by,

F_e = 1.6*10^{-19}*1.5*10^2

F_e = 2.4*10^{-17}N

F=9.36*10^{-19}N

7 0
3 years ago
1. °C= (°F-32) X 5/9. what will be the answer?
aleksley [76]

Answer:

F=9/5(°C)+32

Explanation:

Lets take an example

  • Take 25°C

\\ \sf\longmapsto \dfrac{9}{5}(25)+32

\\ \sf\longmapsto 9(5)+32

\\ \sf\longmapsto 45+32

\\ \sf\longmapsto 77°F

3 0
3 years ago
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