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OLga [1]
3 years ago
12

2 forces are acting on a body. I forgot the body doesn't it's position or shape, the forces.......a)must be of equal magnitude b

)must be parallel and opposite c)must add upto zero d)must be in a single line​
Physics
1 answer:
Veseljchak [2.6K]3 years ago
5 0

Answer:

C

Explanation:

only if there is a net force of zero, the body will not move

some people may say B but that is wrong because maybe one force is greater than the other so the object would still move even though the forces are in opposite directions and parallel

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– A man walks 50 meters due west, then 50 meters 60 north of west. Determine the magnitude and direction of the resultant disp
Fynjy0 [20]

Answer:

86.6, 45°

Explanation:

The diagram explains better.

Using vector component method:

We find the x and y components of the vectors :

For the first:

A = -50cos(0)i + 50sin(0)j

A = -50i

For the second:

B = -50cos(60)i + 50sin(60)j

B = -25i + 43.3j

The resultant vector is :

R = A + B

R = -50i - 25i + 43.3j

R = -75i + 43.3j

The magnitude is:

R = [(-75)² + (43.3)²]^½

R = 86.6m

The angle is

tanθ = (50/50) = 1

θ = 45°

5 0
3 years ago
Read 2 more answers
A spaceship is traveling through deep space towards a space station and needs to make a course correction to go around a nebula.
expeople1 [14]

Answer:

Magnitude = 3.64 × 10^6  

စ = 43.9°

Explanation:

given data

ship to travel = 1.7 × 10^6    kilometers

turn = 70°

travel an additional = 2.7 × 10^6   kilometers

solution

we will consider here

Px = 1.7 × 10^6  

Py = 0

Qx =2.7 × 10^6  cos(70)

Qy= 2.7 × 10^6  sin(70)

so that

Hx = Px + Qx    ............1

Hx = 2.62 × 10^6  

and

Hy = Py + Qy      ..........2

Hy = 2.53 × 10^6  

so Magnitude = \sqrt{((2.62 \times 10^6  )^2+(2.53 \times 10^6)^2)}

Magnitude = 3.64 ×  

so direction  will be

tan စ = Hy ÷ Hx    ......................3

tan စ  = \frac{2.53}{2.62}

tan စ  = 0.9656

စ = 43.9°

3 0
3 years ago
HELPPPPPPP!!!!!!!!!!!!!!!!
joja [24]
Point b since it gains the most height, gaining the most gravitational potential energy

Hope this helps and good luckk u can do thisss :)
6 0
3 years ago
Complete the passage.
nataly862011 [7]

Answer:

Answer: Sound waves and some earthquake waves are longitudinal waves. Ocean, light and other earthquake waves are transverse waves.

Explanation:

There are 2 types of waves:

1. Longitudinal waves: These waves are defined as the waves in which the particles of the medium move in the direction of the wave. This requires a medium to travel. For Example: Sound Waves.

2. Transverse wave: These waves are defined as the waves in which the particles of the medium travel perpendicularly to the direction of the wave. This does not require a medium to travel. These can travel in vacuum also. For Example: Light waves.

Hence, Sound waves and some earthquake waves are longitudinal waves. Ocean, light and other earthquake waves are transverse waves

8 0
3 years ago
The result of changing a physical sound wave into an analogous electrical signal using a transducer (such as a microphone) is ca
Marina CMI [18]

The result of changing a physical sound wave into an analogous electrical signal using a transducer (such as a microphone) is called analogue audio. In this system, the rapid electrical level is directly proportional to the rapid air pressure taken by the transducer. The analogue signal is then augmented and can be kept on an analogue medium such as tape or transformed further into a succession of discrete mathematical numbers. The advantages of using this device is that it yields a subtle sound and is pleasing to the ear by pushing the signal level and overdriving it. But the disadvantages are editing it would be tedious and prone to degradation.

8 0
3 years ago
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