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3 years ago

6

What is the average atomic mass of a sample of naturally occurring x, if it is comprised of the following isotopes 47% ^51X, 17%

^52X and 36% ^56X

1 answer:

iogann1982 [59]3 years ago

8 0

What your going to do is take away the lowest number form the highest and subtract. Thats your answer...

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What is the mass of 2.071x10^14 molecules of SF2

kolezko [41]

Answer:

Name of molecule Sulfur Difluoride ( SF2)

No of Valence Electrons in the molecule 20

Hybridization of SF2 sp3 hybridization

Bond Angles 98 degrees

Molecular Geometry of SF2 Bent

Explanation:

Sulfur Difluoride is an inorganic molecule made up of one Sulphur atom and two Fluorine atoms. It has a chemical formula of SF2 and can be generated by the reaction of Sulphur Dioxide and Potassium Fluoride or Mercury Fluoride. In this blog post, we will look at the Lewis dot structure of SF2, its molecular geometry and shape.

7 0

3 years ago

Which type of substance ionizes completely and creates hydronium ions when dissolved in water?

maw [93]

Answer:

Strong acid

Explanation:

An acid is a substance that interacts with water to produce excess hydroxonium ions in an aqueous solution.

Hydroxonium ions are formed as a result of the chemical bonding between the oxygen of water molecules and the protons released by the acid due to its ionisation. This makes aqueous solution of acids conduct electricity.

A strong acid is one that ionizes almost completely. Examples are:

1. Hydrochloric acid

2. Tetraoxosulphate (VI) acid

3. Trioxonitrate (V) acid

4. Hydroiodic acid

5. Hydrobromic acid

8 0

2 years ago

Read 2 more answers

For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi

natka813 [3]

<u>Answer:</u> The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

<u>For Iron:</u>

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:

$\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol$

For the given chemical reaction:

$2Fe(s)+O_2(g)\rightarrow 2FeO(s)$

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = $\frac{2}{2}\times 0.0771=0.0771mol$ of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:

$0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g$

To calculate the percentage yield of iron (ii) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

$\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%$

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0

2 years ago

Pls give help me out>!

iris [78.8K]

Answer:

3 because it the element that combined the form

7 0

2 years ago

A certain gas is present in a 10.0 LL cylinder at 4.0 atmatm pressure. If the pressure is increased to 8.0 atmatm the volume of

ICE Princess25 [194]

Answer:

The gas obeys Boyle’s law and the value of $k_i\&k_f$ both are equal to 40.0 atm L.

Explanation:

Initial volume of the gas = $V_1=10.0 L$

Initial pressure of the gas = $P_1=4.0 atm$

Final volume of the gas = $V_2=5.0 L$

Final pressure of the gas = $P_2=8.0 atm$

This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

$PV=k$

The equation given by this law is:

$P_1V_1=P_2V_2$

$P_1\propto \frac{1}{V_1}$

$P_1V_1=k_i$

$k_i=4.0 atm\times 10.0 L = 40.0 atm L$

$P_2\propto \frac{1}{V_2}$

$P_V_2=k_f$

$k_f=8.0 atm\times 5.0 L = 40.0 atm L$

$k_i=k_f=40.0 atm L$

The gas in the cylinder is obeying Boyle's law.

The gas obeys Boyle’s law and the value of $k_i\&k_f$ both are equal to 40.0 atm L.

6 0

3 years ago