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podryga [215]
3 years ago
6

What is the average atomic mass of a sample of naturally occurring x, if it is comprised of the following isotopes 47% ^51X, 17%

^52X and 36% ^56X
Chemistry
1 answer:
iogann1982 [59]3 years ago
8 0
What your going to do is take away the lowest number form the highest and subtract. Thats your answer...
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If temperature is increased , the number of collision per second
Tomtit [17]

Answer: increases

Explanation:

Increase in the temperature of a reaction system will cause the molecules of the reactants to possess higher kinetic energy which they would use to travel more randomly in the system, colliding more frequently with other excited molecules and with the wall of the containing vessel.

Thus, if temperature is increased, the number of collision per second also increases.

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What is Catenation in chemistry?​
Eddi Din [679]

Answer:

In chemistry, catenation is the bonding of atoms of the same element into a series, called a chain. A chain or a ring shape may be open if its ends are not bonded to each other, or closed if they are bonded in a ring

Explanation:

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3 years ago
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How many moles of H2O form when 4.5 moles O2 reacts?
mart [117]

Explanation:

Start with a balanced equation.

2H2 + O2 → 2H2O

Assuming that H2 is in excess, multiply the given moles H2O by the mole ratio between O2 and H2O in the balanced equation so that moles H2O cancel.

5 mol H2O × (1 mol O2/2 mol H2O) = 2.5 mol O2

Answer: 2.5 mol O2 are needed to make 5 mol H2O, assuming H2 is in excess.

4 0
3 years ago
Which best explains the statement "It has no definite volume”?
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How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.6 atm) according to 11) the following reaction? Assume t
ddd [48]

Answer:

#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.

Explanation:

Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆

1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.

=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP

2. Calculate moles of F₂ used

=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used

3. Calculate moles of XeF₆ produced from reaction ratios …

Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆

4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number  (6.02 x 10²³ molecules/mole)

=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)

                                  = 2.75 x 10²³ molecules XeF₆.

8 0
3 years ago
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